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Inga [223]
3 years ago
8

Jessica deposited $2000 into an account with a 7.6% annual interest rate, compared quarterly. Assuming that no withdrawals are m

ade, how long will it take for the investment to grow to $3722?
Mathematics
2 answers:
joja [24]3 years ago
8 0

Answer:

Step-by-step explanation:

use

i=prt

i=interest

p= principal value

r=rate

t=time

now you want to find time then it will be

t= i/pr

put values

t= 3722/(2000*7.6%)

t= 2 years

calculation is in fraction but your question given you annual interest so time will also be 2 years not in months

SVEN [57.7K]3 years ago
8 0
Dunno bro FuzfzufRiejFzkduGn hdKguf h
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PLEASE HELP ME ASAP AND THANK YOU
Gwar [14]
Frogs are pretty cool if you ask me:)
3 0
3 years ago
(3+1)²·3 plz help me
xxMikexx [17]

Answer:

Step-by-step explanation:

( 3+1)² * 3

= 4² * 3

= 16 * 3

= 48

6 0
3 years ago
Linear Relationships Study Guide 1.) Select all the equations for which (-6, -1) is a solution. Show your work to prove that eac
TiliK225 [7]

we have point (-6, - 1)

Now we will put these points in each equation,

y = 4x +23

put x = -6 and y = -1

-1 = 4 (-6) +23

-1 = -24 + 23

-1 = -1

LHS = RHS, so this equation has (-6 , -1) as solution.

y = 6x

put x = -6 and y = -1

-1 = 6 (-6)

-1 not= -36

LHS is not equal RHS, so (-6 , -1) is not a solution for that equation,

y = 3x - 5

put x = -6 and y = -1

-1 = 3 (-6) - 5

-1 = -18 - 5

-1 not= -23

LHS is not equal RHS, so (-6 , -1) is not a solution for that equation,

y= 1/6 x

put x = -6 and y = -1

-1 = -6/6

-1 = -1

LHS = RHS, so (-6 , -1) is a solution for that equation,

6 0
1 year ago
The standard form of the equation of a circle is (x−5)2+(y−6)2=1.
Crank

Answer:

(A)x^2+y^2-10x-12y+60=0

Step-by-step explanation:

The standard form of the equation of a circle is given as:

(x-5)^2+(y-6)^2=1

Simplifying the above given equation, we get

x^2+25-10x+y^2+36-12y=1

x^2+y^2-10x-12y+36+25=1

x^2+y^2-10x-12y+61=1

x^2+y^2-10x-12y+60=0

which is the required general form of the equation.

Hence, option A is correct.

3 0
3 years ago
<img src="https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B686x%5E4%20y%5E7%7D" id="TexFormula1" title="\sqrt[3]{686x^4 y^7}" alt="\sqrt
Sergio [31]
This answer is there in picture

5 0
3 years ago
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