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PIT_PIT [208]
3 years ago
11

How to solve this problem

Mathematics
1 answer:
Agata [3.3K]3 years ago
7 0
So first, you have to get two of the same variables to cancel out. Let's do this for x. In order for the x's to cancel out, we could multiply the bottom problem by 2.
(2) 3x-6y=24
After multiplying all the numbers by 2, you get the equation 6x-12y=48
The set of equations is now
-6x+2y=12
6x-12y=48
Now you can add them. The x variables cancel out, so you are left with the y variable.
2y+-12y=-10y and 12+48=60
Then you would divide 60 by -10 to get y=-6.
You would plug the answer for y into one of the original equations, lets do the top one. -6x+2y=12 becomes -6x+2(-6)=12
You'd multiply the 2 and -6 to get -12 so the equation is
-6x-12=12
The negative 12 turn positive and you add to both sides to get the -6x alone.
-6x-12=12
+12=12
-6x=24
Then divide 24 by -6
X=4

(-4,-6) is your final answer.
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Which of the following shows the correct steps in solving the equation?<br> -8x + 3 = 19
Firlakuza [10]

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Step-by-step explanation:

5 0
2 years ago
Read 2 more answers
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USPshnik [31]

Answer:

C $1.75

Step-by-step explanation:

$469 divided by 268 is $1.75, so it's $1.75 per item

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Help urgent plz!❤️❤️❤️Please please urgently
sleet_krkn [62]

Answer:

Problem 2): \left \{x\, |\,0\leq x\leq 240\,\,\right \}

which agrees with answer C listed.

Problem 3) :  D = (-3, 6]  and R = [-5, 7]

which agrees with answer D listed

Step-by-step explanation:

Problem 2)

The Domain is the set of real numbers in which the function (given by a graph in this case) is defined. We see from the graph that the line is defined for all x values between 0 and 240. Such set, expressed in "set builder notation" is:

\left \{x\, |\,0\leq x\leq 240\,\right \}

Problem 3)

notice that the function contains information on the end points to specify which end-point should be included and which one should not. The one on the left (for x = -3 is an open dot, indicating that it should not be included in the function's definition, therefor the Domain starts at values of x strictly larger than -3. So we use the "parenthesis" delimiter in the interval notation for this end-point. On the other hand, the end point on the right is a solid dot, indicating that it should be included in the function's definition, then we use the "square bracket notation for that end-point when writing the Domain set in interval notation:

Domain = (-3, 6]

For the Range (the set of all those y-values connected to points in the Domain) we use the interval notation form:

Range = [-5, 7]

since there minimum y-value observed for the function is at -5 , and the maximum is at 7, with a continuum in between.

6 0
2 years ago
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