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maks197457 [2]
2 years ago
7

A school lunch costs $2.50. A monthly lunch pass costs $40.00. Which inequality represents the number x of lunches you must purc

hase for the monthly pass to be a better deal?
Mathematics
2 answers:
Leya [2.2K]2 years ago
7 0

Answer:

The inequality 2.50x>40.00 represents the number of lunches needed to be purchased for the monthly lunch pass to be a better deal.

Step-by-step explanation:

Given that:

Cost of each lunch = $2.50

Cost of monthly lunch pass = $40.00

Number of lunches = x

For making the monthly pass a better deal, the cost of lunches should be greater than the cost of monthly lunches, therefore

Cost of lunch * Number of lunches > Cost of monthly lunch pass

2.50x > 40.00

Hence,

The inequality 2.50x>40.00 represents the number of lunches needed to be purchased for the monthly lunch pass to be a better deal.

otez555 [7]2 years ago
3 0

Answer:

2.50x > 40.00

$2.50 times a number of lunches is greater than $40.

Step-by-step explanation:

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never [62]

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Answer:

  x = 8

Step-by-step explanation:

By AA similarity, ΔABD ~ ΔCDE. So, corresponding sides are proportional.

  AB/BD = CD/DE

  x/12 = 4/6

  x = 12(4/6)

  x = 8

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How do you write this from least to greatest? 1.265,1.256,1.268
n200080 [17]

Answer:

1.256, 1.265, and 1.268

Step-by-step explanation:


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3 years ago
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Which two points in the graphed function have an average rate of change of 5?
djverab [1.8K]

Answer:

<h2>D. points A and B</h2>

Step-by-step explanation:

Look at the picture.

average\ rate=\dfrac{rise}{run}

A.\ B\ and\ C\to\dfrac{-3}{-1}=3\\\\B.\ D\ and\ F\to\dfrac{-12}{2}=-6\\\\C.\ C\ and\ E\to\dfrac{-8}{4}=-2\\\\D.\ A\ and\ B\to\dfrac{-5}{-1}=5

3 0
2 years ago
There are 3 red marbles, 5 green marbles, and 2 blue marbles in a jar. Event A is defined as drawing a red marble from the jar o
Anastaziya [24]

P(B/A) is \frac{5}{9} in the simplest form

Step-by-step explanation:

Let us explain how to solve the problem

  • P(B|A) is called the "Conditional Probability" of B given A
  • Conditional probability is the probability of one event occurring with some relationship to one or more other events that means event A has already happened, now what is the chance of event B
  • The formula for conditional probability is P(B|A) = P(A and B)/P(A), where P(A and B) is P(A) . P(B given A occurred)

∵ There are 3 red marbles, 5 green marbles, and 2 blue

   marbles in the jar

∴ The total number of the marbles in the jar = 3 + 5 + 2 = 10

∵ Two marbles are drawn from the bag, one after the other without

   replacement

- That means red is already occurred when green is happened,

  so it is a "Conditional Probability" of green given red

  P(B/A) = P(A and B)/P(A)

∵ Event A is defined as drawing a red marble from the jar on

   the first draw

∴ P(A) = P(red)

∵ P(red) = \frac{3}{10}

∴ P(A) = \frac{3}{10}

∵ Event B is defined as drawing a green marble on the second draw

∴ P(B) = P(green)

- The number of marbles after the red is chosen is 9

∵ P(green) = \frac{5}{9}

∴ P(B) = \frac{5}{9}

- Find P( A and B)

∴ P(A and B) = ( \frac{3}{10} ) . ( \frac{5}{9} )

∴ P(A and B) = \frac{15}{90}

- Simplify the fraction by divide up and down by 15

∴ P(A and B) = \frac{1}{6}

∵ P(B|A) = P(A and B)/P(A)

- Substitute the values of P(A and B) and P(A) in the rule above

∴ P(B/A) = \frac{\frac{1}{6}}{\frac{3}{10}}

- Simplify the fraction

∵ \frac{1}{6} ÷ \frac{3}{10} = \frac{1}{6} × \frac{10}{3} = \frac{10}{18}

- Divide up and down by 2

∴ P(B/A) = \frac{5}{9}

P(B/A) is \frac{5}{9} in the simplest form

Learn more:

You can learn more about probability in brainly.com/question/10744457

#LearnwithBrainly

7 0
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ELEN [110]

Answer:

(a) 3a^4 - 11a^2b^2 -2b^4

(b) 3a^4 - 11a^2b^2 -2b^4= 2

Step-by-step explanation:

Given

(a^4 - 6a^2b^2+ b^4) - (-2a^4+5a^2b^2+ 3b^4)

Solving (a): Simplify

(a^4 - 6a^2b^2+ b^4) - (-2a^4+5a^2b^2+ 3b^4)

Open brackets

a^4 - 6a^2b^2+ b^4 +2a^4-5a^2b^2- 3b^4

Collect Like Terms

a^4 +2a^4- 6a^2b^2-5a^2b^2+ b^4 - 3b^4

Simplify Like Terms

3a^4 - 11a^2b^2 -2b^4

Solving (b): Simplify when a = 2 and b = -1

3a^4 - 11a^2b^2 -2b^4

3*(2)^4 - 11*(2^2)*(-1)^2 -2*(-1)^4

3 * 16 - 11 * 4 * 1 - 2 * 1

48 - 44 - 2

= 2

Hence:

3a^4 - 11a^2b^2 -2b^4= 2

4 0
2 years ago
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