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2 answers:
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Answer
The total area of the squares = 29 square cm
The triangle is not a right-angled triangle
Step-by-step explanation:
We are given three squares
The first square has a length of 4cm
The second square has a length of 3cm
The third square has a length of 2cm
Part A
Total area = Area of square 1 + Area of square 2 + Area of square 3
Area of a square = l^2
Where l is the length of the square
Area of a square 1 = 4^2
Area of a square = 16 square cm
Area of square 2 = 3^2
Area of square 2 = 9 square cm
Area of square 3 = 2^2
Area of square 3 = 4 square cm
Total area of the square = 16 + 9 + 4
The total area of the square = 29 square cm
Hence, the total square of the figure is 29 square cm
Part B
We assume that
if xy=0
x and y=0
first make it equal to zero
minus 5 on both sides
4x^2-12x+4=0
undistribute 4 for ease
4(x^2-3x+1)=0
since 4 does not equal zero, and the only thing that will get it to zero is 0,
x^2-3x+1=0
use quadratic equation
if you hahve
ax^2+bx+c=0
x=
1x^2-3x+1=0
a=1
b=-3
c=1
x=
x=
x=
x=
or 
aprox
x=2.61803 or 0.381966
if xy=0
x and y=0
first make it equal to zero
minus 5 on both sides
4x^2-12x+4=0
undistribute 4 for ease
4(x^2-3x+1)=0
since 4 does not equal zero, and the only thing that will get it to zero is 0,
x^2-3x+1=0
use quadratic equation
if you hahve
ax^2+bx+c=0
x=
1x^2-3x+1=0
a=1
b=-3
c=1
x=
x=
x=
x=
aprox
x=2.61803 or 0.381966
Answer:
No value of x
Step-by-step explanation:
SEE the image for solution.
HOPE it helps
Have a great day
