Um i would need more details
But i thing you would add those together
Answer:
ASA
Step-by-step explanation:
In given triangle
Line BC = Line QR
Angle ABC = Angle PQR
Angle ACB = Angle PRQ
Computation:
Angle ABC = Angle PQR (Angle)
Line BC = Line QR (Side)
Angle ACB = Angle PRQ (Angle)
So,
ΔABC ≅ ΔPQR
By Angle Side Angle property
ASA
Answer: The points of the images are (9,10), (15,6), (6,4) and the image is not a rigid motion because the shape changes in side.
Step-by-step explanation:
Since it gives you the scale factor then find they coordinates by multiplying the coordinates by the scare factor.
A(3,5) → (3*3,5*2) → (9,10)
B( 5,3) → (5*3, 3*2) → (15,6)
C ( 2,3)→ (2*3, 2*2)→ ( 6,4)
We turn -5,12 into polar coordinates. It's a Pythagorean Triple so
r = 13 Ф=arctan(-12/5) + 180° ( in the second quadrant )
so -5 = 13 cos Ф, 12 = 13 sin Ф
12 sin x - 5 cos x = 6.5
13 sinФ sin x + 13 cos Ф cos x = 6.5
13 cos(x - Ф) = 6.5
cos(x - Ф) = 1/2
cos(x - Ф) = cos 60°
x - Ф = ± 60° + 360° k integer k
x = Ф ± 60° + 360° k
x = 180° + arctan(-12/5) ± 60° + 360° k
That's the exact answer;
x ≈ 180° - 67.38° ± 60° + 360° k
x ≈ 122.62° ± 60° + 360° k
x ≈ { 62.62°, 182.62°} + 360° k, integer k
