It is equivalent I believe...hope this helps!
Hello,
If we want to factor the expression, we have to solve
3x² + 10x + 8 = 0
a = 3 ; b = 10 ; c = 8
∆ = b² - 4ac = 10² - 4 × 3 × 8 = 4 > 0
x1 = (-b - √∆)/2a = (-10 - 2)/6 = -12/6 = -2
x2 = (-b + √∆)/2a = (-10 + 2)/6 = -8/6 = -4/3
Factor :
a (x - x1)(x - x2)
= 3(x + 2)(x + 4/3)
= (x + 2)(3x + 4)
Answer:
Step-by-step explanation:
Compounding interest :
Future value of money = Present value * (1+ r)^N
r - interest rate
n - number of period
In our example, Present value = 325.76, FV = 400, r = 2%, and we need to find N
by solving that we can find it that N is equal to 10.3675
Simple interest :
400 - 325.76 = 74.26$ we need to increase
325.76*2% = 6.5152$ each year
74.26 / 6.5152 = 11.3949
as a whole year = 12years
The units are ordered smallest to largest from top to bottom:
Picometer (pm) = 1 x 10⁻¹² meters
Nanometer (nm) = 1 x 10⁻⁹ meters
Micrometer (um) = 1 x 10⁻⁶ meters
Millimeter (mm) = 1 x 10⁻³ meters
Centimeter (cm) = 1 x 10⁻² meters
Decimeter (dm) = 1 x 10⁻¹ meters
Meters (m) = 1 meter
Kilometers (Km) = 1 x 10³ meters
Answer:
$29,005.97
Step-by-step explanation:
Cn = Co * (1 + i)^n
Cn = 104,986.99(1+.05/1)^(1*5)
Cn = 104,986.99(1+.05)^5
Cn = 104,986.99(105)^5
Cn = 104,986.99(1.2763)
Cn = 133,992.96, total money at end
133,992.96-104,986.99= $29,005.97, interest accumulated
