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AfilCa [17]
3 years ago
14

The perimeter of a rectangle is 20 centimeters. The length is 6 centimeters. What is the area of the rectangle?

Mathematics
2 answers:
I am Lyosha [343]3 years ago
3 0
2x + 2y = 20
2(6) + 2y = 20
12 + 2y = 20
2y = 8
y = 4
width = 4

Area = 6 × 4
= 24 cm
konstantin123 [22]3 years ago
3 0
Perimeter minus the length is 14, so 14 x 6 would equal the area. so the area of the rectangle is 84
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Answer:

"landing on a shaded portion and landing on a 3"

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Step-by-step explanation:

Mutually exclusive means the events will have no intersection.

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"landing on a shaded portion and landing on an even number"

Landing on a shaded portion would be 1 or 4.

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"landing on a shaded portion and landing on a number greater than 3"

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Landing on a number greater than 3 would be just 4.

There is an intersection; they both contain 4.

These events are not mutually exclusive.

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"landing on a shaded portion and landing on a 3"

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Landing on 3 would just be 3.

There is no common elements in the lists listed.  These events have no intersection.

These events are mutually exclusive.

Let's look at your fourth choice:

"landing on an unshaded portion and landing on an odd number"

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These events are not mutually exclusive.

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"landing on an unshaded portion and landing on a number less than 2 "

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see explanation

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tan(A+B) = \frac{tanA+tanB}{1-tanAtanB} = 1 ← from above

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(Prove) The angle subtended by an arc at the center is double the angle subtended by it at any
Pavlova-9 [17]

Answer:

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Step-by-step explanation:

Let us consider the image attached.

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\angle AOB = 2 \times \angle APB

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Using external angle property, that external angle is equal to sum of two opposite internal angles of a triangle.

\angle AOQ = \angle PAO + \angle OPA=2 \times \angle APO .... (1)

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And angles opposite to equal sides of a triangle are also equal in a triangle.

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Using external angle property, that external angle is equal to sum of two opposite internal angles of a triangle.

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Now, we can see that:

\angle AOB = \angle AOQ+\angle BOQ

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