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andrew-mc [135]
3 years ago
7

How do you make this statement true

Mathematics
1 answer:
Semenov [28]3 years ago
3 0
The answer is the absolute value of -13 is thirteen and the absolute value of 15 is 15 so I-13I<I15I
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Does this table represent a function? Why or why not?
ivanzaharov [21]
In order to be a function, every x-value must correspond to only one y-value.

Answer: D
3 0
3 years ago
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A girl is 18 years old and her brother is a third of her age. When the girl is 36 what would be the age of the brother?
ale4655 [162]
First we need to calculate how many years her brother has when she is 18. As text says he is:
18/3 = 6 years old

Now when she gains another 18 years (36-18=18) he will also gain those 18 years

When she is 36 he will have 6+18=24 years old

Answer is 24.
8 0
3 years ago
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Addition fractions 2 5/7+6/7=​
kupik [55]

Answer:

The answer is: 3 4/7

Step-by-step explanation:

2 5/7+6/7

=2+11/7

=2+1 4/7

=3 4/7

Hope it helps!

8 0
3 years ago
4/5 + 5/6 + 7/2 equals what
Zanzabum
Equal to 5.13333...
Or 77/15
3 0
3 years ago
A welder requires 18 hours to do a job. After the welder and an apprentice work on a job for 6 hours, the welder moves to anothe
Dafna1 [17]

Answer:

the apprentice can complete the job in 30 hours by working alone.

Step-by-step explanation:

Given:

Number of hours required to complete a job by welder = 18 hours

Number of hours welder work on job = 6 hours.

Number of hours required by apprentice to complete the job = 14 hours

We need to find Number of hours required to complete a job by apprentice alone.

Solution:

Let Number of hours required to complete a job by apprentice alone be 'a'.

Also let the job completed be = 1

Now we know that ;

Time required on job is equal to sum of Number of hours welder work on job and Number of hours required by apprentice to complete the job.

framing in equation form we get

Time required on job =  6+14 =20\ hrs

Now we can say that;

each has done a fraction of the work so we will add to two fraction as number of hours of work done by Total number of hours required to do the work to complete 1 job.

so we can frame the equation as;

\frac{6}{18}+\frac{20}{a}=1

By reducing the fraction we get;

\frac{1}{3}+\frac{20}{a}=1

Now we will make the denominator common to solve the fraction we get;

\frac{1\times a}{3\times a}+\frac{20\times3}{a\times3}=1\\\\\frac{a}{3a}+\frac{60}{3a}=1

Now denominators are same so we will solve the numerator we get;

\frac{a+60}{3a}=1

Multiplying both side by 3a we get;

\frac{a+60}{3a}\times3a=1\times 3a\\\\a+60=3a

Combining the like terms we get;

3a-a=60\\\\2a=60

Dividing both side by 2 we get;

\frac{2a}{2}=\frac{60}{2}\\\\a=30\ hrs

Hence the apprentice can complete the job in 30 hours by working alone.

4 0
2 years ago
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