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gogolik [260]
3 years ago
5

Doc decides to buy the entire 6th grade a slice of pizza.

Mathematics
2 answers:
miv72 [106K]3 years ago
8 0

Answer:

Sorry, This is not a question

Step-by-step explanation:

N/A

photoshop1234 [79]3 years ago
6 0

Answer:what

Step-by-step explanation:

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Given that (2,8) is on the graph of f(x),find the corresponding point for the function -3/4 f(x)
yuradex [85]

Answer:

Corresponding point to (2,8) along -3/4 f(x) = ( -1.5 , -6 )

Explanation:

 When a graph f(x) is multiplied by a factor k, the points on the graph also changes by (kx, ky).

Here it is given that (2,8) is on the graph of f(x)

Now we need to find corresponding point to (2,8) along -3/4 f(x)

x - coordinate = \frac{-3*2}{4} =-1.5

y - coordinate = \frac{-3*8}{4} =-6

So corresponding point to (2,8) along -3/4 f(x) = ( -1.5 , -6 )

8 0
3 years ago
Draw a quadrilateral that does not belong, then explain why. What should I draw and write?​
Anna007 [38]

Answer

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Step-by-step explanation:

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3 years ago
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Nady [450]

Answer:

Step-by-step explanation:

a. 1 & 2

b. 3 & 5

c. 2/15

d. 2/5 x 5/3

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8 0
3 years ago
Find the value of kk for which the constant function x(t)=kx(t)=k is a solution of the differential equation 5t3dxdt+2x−2=05t3dx
uranmaximum [27]
Given the differential equation

5t^3 \frac{dx}{dt} +2x-2=0

The solution is as follows:

5t^3 \frac{dx}{dt} +2x-2=0 \\  \\ \Rightarrow5t^3 \frac{dx}{dt} =2-2x \\  \\ \Rightarrow \frac{5}{2-2x} dx= \frac{1}{t^3} dt \\  \\ \Rightarrow \int {\frac{5}{2-2x} } \, dx = \int {\frac{1}{t^3}} \, dt \\  \\ \Rightarrow- \frac{5}{2} \ln(2-2x)=- \frac{1}{2t^2} +A \\  \\ \Rightarrow\ln(2-2x)= \frac{1}{5t^2} +B\\  \\ \Rightarrow2-2x=Ce^{\frac{1}{5t^2}} \\  \\ \Rightarrow 2x=Ce^{\frac{1}{5t^2}}+2 \\  \\ \Rightarrow x=De^{\frac{1}{5t^2}}+1
3 0
3 years ago
Question 2
Tasya [4]

Answer:

24x+48  using the <u>distributive property.</u>

Step-by-step explanation:

5 0
4 years ago
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