The overdraft transaction will be successful and $45 will be paid at the grocery store but there will be an overdraft charges in addition to $15.
Overdraft is a privilege granted to checking account holder which good credit record.
- Overdraft privilege allows payment for transaction even though there's not enough funds in the bank account to fully cover the transaction.
- An Overdraft Fees will be charged for the service provided by the bank in addition to the amount provided to the bank-holder.
In conclusion, the payment at the grocery store will be successful but the account will be in negative of $15 and an overdraft fee will be charged by the bank as well.
Read more on Overdraft here
<em>brainly.com/question/17154998</em>
Answer:
PCM encoded samples from 24 voice band channels
Explanation:
The Multiplexer from a lot of inputs generates one single output. And it is the select line that determines which of the input is going to influence output. And the select lines determine the increase in the quantity of data that can be sent through the network in a given amount of time. And this is termed as a data selector. Please note, this is application of multiplexer in data transmission.
And now coming to the T1 carrier system, it is a time division multiplexor, which multiplexes the PCM encoded samples coming from 24 band channels that require to be transmitted over an optical fiber or single metallic wire pair. And for this question, we need what is being multiplexed, and that is as mentioned in the Answer section.
If your computer is old it may be the screen is dying or if its brand new it would probably be the power supply check your battery or cables
Answer:
Program is written in C++
#include<iostream>
using namespace std;
int main()
{
//1. Prime Number
int num;
cout<<"Input Number: ";
cin>>num;
int chk = 0;
for(int i =2; i <num;i++)
{
if(num%i==0)
{
chk = 1;
break;
}
}
if(chk == 0)
{
cout<<num<<" is prime"<<endl;
}
else
{
cout<<num<<" is not prime"<<endl;
}
//2. Greatest Common Factor
int num1, num2, x, y, temp, gcf;
cout<<"Enter two numbers: ";
cin>>num1;
cin>>num2;
x = num1;
y = num2;
while (y != 0) {
temp = y;
y = x % y;
x = temp;
}
gcf = x;
cout<<"Greatest Common Factor: "<<gcf<<endl;
// 3. LCM
cout<<"Enter two numbers: ";
cin>>num1;
cin>>num2;
x = num1;
y = num2;
while (y != 0) {
temp = y;
y = x % y;
x = temp;
}
gcf = x;
int lcm =(num1 * num2)/gcf;
cout<<"Least Common Multiple: "<<lcm<<endl;
return 0;
}
Explanation:
<em>I've added the full source code as an attachment where I make use of comments to explain some lines</em>
