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sergejj [24]
3 years ago
10

Someone please help me!

Mathematics
1 answer:
Radda [10]3 years ago
7 0

Answer:

dude don't you have notes

Step-by-step explanation:

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Eddie opens a bank account with $1,000. Every year he doubles the amount of money in the account.
Sveta_85 [38]

Answer:

next year he'll add $2,000. to the bank account. the total amount would be <u>$3,000.00</u>

Step-by-step explanation:

$1,000.00 x 2 = $2,000.00 + $1,000.00 = $3,000.00

^w^

5 0
3 years ago
What is 3x +2- 7x = -14
Alecsey [184]

Answer:

4

Step-by-step explanation:

3x<u>+2</u>-7x=<u>-14</u>

3x-7x=-14-2

-4x=-16 /:(-4)

x=4

5 0
3 years ago
Suppose that the members of a student governance committee will be selected from the 40 members of the student senate. There are
Len [333]

Answer:

The total number of ways to form a student governance committee is 1,211,760.

Step-by-step explanation:

The students senate consists of a total of 40 students.

The students are either Sophomores or Juniors or Seniors.

The number of students in each of these categories are as follows:

Sophomores = 18

Juniors = 12

Seniors = 10

A governance committee have to be selected from the students senate.

The committee have to made up of 2 sophomores, 2 juniors and 3 seniors.

Combinations can be used to select 2 sophomores from 18, 2 juniors from 12 and 3 seniors from 10.

Combinations is a mathematical technique used to determine the number of ways to select <em>k</em> items from <em>n</em> distinct items.

The formula is:

{n\choose k}=\frac{n!}{k!(n-k)!}

(1)

Compute the number of ways to select 2 sophomores from 18 as follows:

{n\choose k}=\frac{n!}{k!(n-k)!}

{18\choose 2}=\frac{18!}{2!(18-2)!}=\frac{18\times 17\times 16!}{2\times 16!}=153

Thus, there are 153 ways to select 2 sophomores from 18.

(2)

Compute the number of ways to select 2 juniors from 12 as follows:

{n\choose k}=\frac{n!}{k!(n-k)!}

{12\choose 2}=\frac{12!}{2!(12-2)!}=\frac{12\times 11\times 10!}{2\times 10!}=66

Thus, there are 66 ways to select 2 juniors from 12.

(3)

Compute the number of ways to select 3 seniors from 10 as follows:

{n\choose k}=\frac{n!}{k!(n-k)!}

{10\choose 3}=\frac{10!}{3!(10-3)!}=\frac{10\times 9\times 8\times 7!}{2\times 3\times 7!}=120

Thus, there are 120 ways to select 3 seniors from 10.

The total number of ways to form a student governance committee that must have 2 sophomores, 2 juniors and 3 seniors is:

Total number of ways = {18\choose 2}\times {12\choose 2}\times {10\choose 3}

                                    =153\times 66\times 120\\=1211760

Thus, the total number of ways to form a student governance committee is 1,211,760.

7 0
3 years ago
VsgsscNw d dhdnBskele r. Eheu
irina1246 [14]
Lzlsjxkskalsokxjxjsks :)!
6 0
4 years ago
When a truckload of apples arrives at a packing plant, a random sample of 125 apples are selected and examined for bruises and o
valentinak56 [21]

Answer:

You would need to go 1.6 standard errors away from 0.09.

Step-by-step explanation:

We can solve this using the normal distribution, because, by the Central Limit Theorem, the sampling distribution of the sample proportions is approximately normal.

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

89% of the sample proportions.

50 - 89/2 = 5.5th percentile

50 + 89/2 = 94.5th percentile

5.5th percentile

X when Z has a pvalue of 0.055. So X when Z = -1.6.

So 1.6 standard error away from 0.09.

94.5th percentile

X when Z has a pvalue of 0.945. So X when Z = 1.6.

So 1.6 standard error away from 0.09.

You would need to go 1.6 standard errors away from 0.09.

3 0
4 years ago
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