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Gemiola [76]
3 years ago
15

Whats 83÷3 using reminders Please help!

Mathematics
2 answers:
Andre45 [30]3 years ago
3 0
It's gonna be 27 r 6
aleksandrvk [35]3 years ago
3 0
83÷3=27666666667 and that how i got my answer because i cont by 100 and that my answer.
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Help with 5b please . thank you.​
Allushta [10]

Answer:

See explanation

Step-by-step explanation:

We are given f(x)=ln(1+x)-x+(1/2)x^2.

We are first ask to differentiate this.

We will need chain rule for first term and power rule for all three terms.

f'(x)=(1+x)'/(1+x)-(1)+(1/2)×2x

f'(x)=(0+1)/(1+x)-(1)+x

f'(x)=1/(1+x)-(1)+x

We are then ask to prove if x is positive then f is positive.

I'm thinking they want us to use the derivative part in our answer.

Let's look at the critical numbers.

f' is undefined at x=-1 and it also makes f undefined.

Let's see if we can find when expression is 0.

1/(1+x)-(1)+x=0

Find common denominator:

1/(1+x)-(1+x)/(1+x)+x(1+x)/(1+x)=0

(1-1-x+x+x^2)/(1+x)=0

A fraction can only be zero when it's numerator is.

Simplify numerator equal 0:

x^2=0

This happens at x=0.

This means the expression,f, is increasing or decreasing after x=0. Let's found out what's happening there. f'(1)=1/(1+1)-(1)+1=1/2 which means after x=0, f is increasing since f'>0 after x=0.

So we should see increasing values of f when we up the value for x after 0.

Plugging in 0 gives: f(0)=ln(1+0)-0+(1/2)0^2=0.

So any value f, after this x=0, should be higher than 0 since f(0)=0 and f' told us f in increasing after x equals 0.

8 0
2 years ago
What is the slope of a line that is perpendicular to the line whose equation is 0.52 - 5y = 9?
otez555 [7]
The slope is 0.1
To find a perpendicular slope, find the negative reciprocal.
The reciprocal of 0.1 is 10
The negative of 10 is -10
Final answer:-10
7 0
3 years ago
Combine Like Terms and Eliminate Parenthesis.<br>5z-[2z-(13z+8)]
katen-ka-za [31]

We need to start from the innermost parenthesis and work our way out.

The first parenthesis is 13z+8. These are not like terms because one involves a variable, while the other is a constant term. Two terms are summable if they involve the same power(s) of the same variable(s).

So, we can take one step outwards, and we arrive to the square brackets. We have

2z-13z-8

and 2z and -13z are like terms, so we can sum them:

2z-(13z +8) = 2z-13z-8 = (2-13)z-8 = -11z-8

Finally we arrive to the whole expression, which is

5z-(-11z-8) = 5z+11z+8 = (5+11)z+8=16z+8

Because, again, 5z and 11z were like terms.

6 0
3 years ago
PLEASE HELP FAST AND PLEASE DON'T POST A LINK
Likurg_2 [28]

Answer:

The difference in amount = $430

Step-by-step explanation:

1- Annual contract:

The annual contract means a contract for 12 months. There is a month penalty for breaking the lease.  

This means that, if you left after 8 months, you will have to pay for 10 month.

Total paid = monthly payment * 10

Total paid = 535 * 10 = $5350

2- Month-to-month contract:

You will only paid for the 8 months you stayed,

Total paid = monthly payment * 8

Total paid = 615 * 8 = $4920

3- Getting the difference:

We can note that a month-month contract is a better option if you intend to stay for only 8 months

Difference = 5350 - 4920 = $430

Hope this helps :)

4 0
3 years ago
Read 2 more answers
A parabola can be drawn given a focus of (-11, -2) and a directrix of x= -3
fgiga [73]

Check the picture below, so the parabola looks more or less like that.

now, the vertex is half-way between the focus point and the directrix, so that puts it where you see it in the picture, and the horizontal parabola is opening to the left-hand-side, meaning that the distance "P" is negative.

\textit{horizontal parabola vertex form with focus point distance} \\\\ 4p(x- h)=(y- k)^2 \qquad \begin{cases} \stackrel{vertex}{(h,k)}\qquad \stackrel{focus~point}{(h+p,k)}\qquad \stackrel{directrix}{x=h-p}\\\\ p=\textit{distance from vertex to }\\ \qquad \textit{ focus or directrix}\\\\ \stackrel{"p"~is~negative}{op ens~\supset}\qquad \stackrel{"p"~is~positive}{op ens~\subset} \end{cases} \\\\[-0.35em] \rule{34em}{0.25pt}

\begin{cases} h=-7\\ k=-2\\ p=-4 \end{cases}\implies 4(-4)[x-(-7)]~~ = ~~[y-(-2)]^2 \\\\\\ -16(x+7)=(y+2)^2\implies x+7=-\cfrac{(y+2)^2}{16}\implies x=-\cfrac{1}{16}(y+2)^2-7

8 0
2 years ago
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