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LuckyWell [14K]
4 years ago
12

How do I find x on lines​

Mathematics
1 answer:
LUCKY_DIMON [66]4 years ago
3 0

The center line that goes from left to right is your x axis and the line that goes from top to bottom is you y axis

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In equation 1/4n+5=5 1/2 is equal to​
Pie
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3 years ago
a senator wishes to estimate the proportion of united states voters who favor new road construction. what size sample should be
Nitella [24]

The  size of the sample should be obtained at 2401 in order to be 95% confident

Given that:

Margi of error, ME=0.02

Population proportion, p=0.50

To Find: The size of the sample that should be obtained in order to be 95% confident

Let the size of the sample be n

Using formula,

n=(p*(1-p))*(z(0.05/2)/ME)^{2} \\n=(0.5*(1-0.5))*(1.96/0.02)^{2} \\n=0.25*9604\\n=2401

Therefore, the size of the sample should be obtained at 2401 in order to be 95% confident

Learn more about Population proportion here brainly.com/question/15703406

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8 0
3 years ago
WILL MARK BRAINLIEST!<br> What is the value of g?
pav-90 [236]

Answer:

∠g = 142°

Step-by-step explanation:

∠g = 180 - 38 = 142°

7 0
3 years ago
Determine the circumference of<br>a circle with diameter 28 cm. Show your work​
gulaghasi [49]

Answer:

Step-by-step explanation:

Diameter = 28 cm

therefore, radius = 28 / 2 = 14 cm

Circumference = 2 π r

= 2 × 22 / 7 × 14

= <u><em>88 cm</em></u>

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8 0
4 years ago
Read 2 more answers
Two hundred undergraduate students were randomly selected from a university that has 47,000 students in total. Systolic blood pr
Hoochie [10]

Answer:

The  correct option is d

Step-by-step explanation:

From the question we are told that

    The  population size is  N  =  47000

    The  sample size is  n  =  200

     The  sample mean is   \= x  =  118.0 \ mmHg

     The  standard deviation is  \sigma  =  11.0 \ mmHg

     

Given that the confidence level is  95% then the level of significance can be calculated as

                     \alpha  =  100 -  95

                    \alpha  =  5 \%

                      \alpha  =  0.05

Next we obtain the critical value of  \frac{\alpha }{2} from  z-table , the value is  Z_{\frac{\alpha }{2}  } =  Z_{\frac{0.05 }{2}  } = 1.96

The reason we are obtaining critical value of   \frac{\alpha }{2} instead of    \alpha is because  

 \alpha represents the area under the normal curve where the confidence level interval (   1-\alpha) did not cover which include both the left and right tail while  

 \frac{\alpha }{2}  is just the area of one tail which what we required to calculate the margin of error .

NOTE: We can also obtain the value using critical value calculator (math dot armstrong dot edu)

  Generally the margin of error is mathematically represented as

            E  =  Z_{\frac{\alpha }{2} } *\frac{\sigma }{ \sqrt{n} }

substituting values

           E  =  1.96 *\frac{11.0  }{ \sqrt{200} }

           E  = 1.5245

The  95% confidence level interval is mathematically represented as

       \= x  -  E < \mu < \= x  +  E

substituting values

       118.0   -  1.5245 < \mu < 118.0   +  1.5245

        116.5< \mu < 119.5

         [116.5 , 119.5]

 

6 0
3 years ago
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