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bezimeni [28]
2 years ago
12

a senator wishes to estimate the proportion of united states voters who favor new road construction. what size sample should be

obtained in order to be 95% confident
Mathematics
1 answer:
Nitella [24]2 years ago
8 0

The  size of the sample should be obtained at 2401 in order to be 95% confident

Given that:

Margi of error, ME=0.02

Population proportion, p=0.50

To Find: The size of the sample that should be obtained in order to be 95% confident

Let the size of the sample be n

Using formula,

n=(p*(1-p))*(z(0.05/2)/ME)^{2} \\n=(0.5*(1-0.5))*(1.96/0.02)^{2} \\n=0.25*9604\\n=2401

Therefore, the size of the sample should be obtained at 2401 in order to be 95% confident

Learn more about Population proportion here brainly.com/question/15703406

#SPJ4

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Answer:

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Step-by-step explanation:

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3 years ago
There are 20 machines in a factory. 7 of the machines are defective.
adelina 88 [10]

Answer:

0.1225

Step-by-step explanation:

Given

Number of Machines = 20

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Required

Probability that two selected (with replacement) are defective.

The first step is to define an event that a machine will be defective.

Let M represent the selected machine sis defective.

P(M) = 7/20

Provided that the two selected machines are replaced;

The probability is calculated as thus

P(Both) = P(First Defect) * P(Second Defect)

From tge question, we understand that each selection is replaced before another selection is made.

This means that the probability of first selection and the probability of second selection are independent.

And as such;

P(First Defect) = P (Second Defect) = P(M) = 7/20

So;

P(Both) = P(First Defect) * P(Second Defect)

PBoth) = 7/20 * 7/20

P(Both) = 49/400

P(Both) = 0.1225

Hence, the probability that both choices will be defective machines is 0.1225

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Step-by-step explanation:

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