Question

(PLEASE HELP)

Answer 1

Answer:

Option A is correct that is 64 leaves would be there.

Step-by-step explanation:

Total Number of ties = 8

Total number of shirts = 2

Total number of jackets = 4

No of ties have to be chosen = 1

No of shirt have to be chosen = 1

No of jacket have to be chosen = 1

we use combination to find number of ways,

$^{n}\textrm{C}_{r}=\frac{n!}{r!\,(n-r)!}$

No way of choosing a tie = $^{8}\textrm{C}_{1}=\frac{8!}{1!\,(8-1)!}=\frac{8!}{1!\,7!}=8$

No way of choosing a shirt = $^{2}\textrm{C}_{1}=\frac{2!}{1!\,(2-1)!}=\frac{2!}{1!\,1!}=2$

No way of choosing a jacket = $^{4}\textrm{C}_{1}=\frac{4!}{1!\,(4-1)!}=\frac{4!}{1!\,3!}=4$

Total Number of ways of selection = 2 × 4 × 8 = 64

Therefore, Option A is correct that is 64 leaves would be there.

Answer 2

A)64 it 2*4*8=64 it is multiplied