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Sveta_85 [38]
4 years ago
12

Solve the following equation when x = 2 and y = 4 . 3x + 2y + 4 =

Mathematics
2 answers:
alukav5142 [94]4 years ago
7 0

Answer:

6+8+4=18

Step-by-step explanation:

Brilliant_brown [7]4 years ago
6 0

Answer:

18

Step-by-step explanation:

3(2) + 2(4) + 4

3(2)=6

2(4)=8

6+8+4=18

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PolarNik [594]

Answer:

A) Q(x) = (x + 3)² + 5, and the vertex is (-3, 5)

B) R(x) = (x - 3)² + 2, and the vertex is (3, 2)

C) S(x) = (x - 1)² - 5, and the vertex is (1, -5)

Step-by-step explanation:

The given function is P(x) = (x + 3)² + 2

The given function is a parabolic function in vertex form, f(x) = a·(x - h)² + k, and vertex, (h, k)

By comparison, the vertex of the function P(x) = (x + 3)² + 2 is (-3, 2)

A) A function f(x) translated α units UP gives

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A translation of the function 3 units UP is given by adding 3 to the given function as follows;

Q(x) = P(x) + 3

∴ Q(x) = (x + 3)² + 2 + 3 = (x + 3)² + 5

Q(x) = (x + 3)² + 5, and the vertex by comparison to f(x) = a·(x - h)² + k, and vertex, (h, k) is (-3, 5)

B) A function f(x) translated <em>b</em> units RIGHT gives;

f(x) translated <em>b</em> units right → f(x - b)

∴ P(x) = (x + 3)² + 2 translated 6 units RIGHT gives;

P(x) = (x + 3)² + 2 (translated 6 units RIGHT) → R(x) = (x + 3 - 6)² + 2 = (x - 3)² + 2

R(x) = (x - 3)² + 2, and the vertex by comparison is (3, 2)

C) A function translated α units DOWN and <em>b</em> units RIGHT is given as follows;

f(x) \ translated \ by\  \dbinom{b}{a} \rightarrow f(x - b) - a

Therefore, the given function, P(x) = (x + 3)² + 2, translated 7 units DOWN and 4 units RIGHT gives;

P(x) = (x + 3)^2 + 5 \ translated \ by\  \dbinom{4}{-7} \rightarrow P(x - 4) - 7 = S(x)

S(x) = P(x - 4) - 7 = (x + 3 - 4)² + 2 - 7 = (x - 1)² - 5

P(x) = (x + 3)^2 + 5 \ translated \ by\  \dbinom{4}{-7} \rightarrow (x - 1)^2 - 5= S(x)

S(x) = (x - 1)² - 5, and the vertex by comparison is (1, -5)

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