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Sveta_85 [38]
3 years ago
12

Solve the following equation when x = 2 and y = 4 . 3x + 2y + 4 =

Mathematics
2 answers:
alukav5142 [94]3 years ago
7 0

Answer:

6+8+4=18

Step-by-step explanation:

Brilliant_brown [7]3 years ago
6 0

Answer:

18

Step-by-step explanation:

3(2) + 2(4) + 4

3(2)=6

2(4)=8

6+8+4=18

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What is the solution set to the inequality (4x-3)(2x-1)=> 0?
Varvara68 [4.7K]

Answer:

please send help thier is someone doing stupid noises

Step-by-step explanation:

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6 0
3 years ago
Read 2 more answers
The equation of the circle is (x+8)^2+(y+9)^2=169. Which of the following are the center and the radius of the circle
ipn [44]
The equation for a circle is (x - h)^2 + (y - k)^2 = r^2
where (h, k) is the center and r is the radius
(x + 8)^2 + (y + 9)^2 = 169
Since the equation is -h and -k, I will rewrite in terms of -h and -k.
(x - -8)^2 + (y - -9)^2 = 13^2
The center is (-8, -9) and the radius = 13
Let me know if you need me to explain further.
3 0
3 years ago
Jollibee employs a total of 10 cashiers and 15 kitchen crews. The manager selects a team of 2 cashiers and
Airida [17]

Answer:

The manager can select a team in 61425 ways.

Step-by-step explanation:

The order in which the cashiers and the kitchen crews are selected is not important. So we use the combinations formula to solve this question.

Combinations formula:

C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

In how many ways can the manager select a team?

2 cashiers from a set of 10.

4 kitchen crews from a set of 15. So

T = C_{10,2}*C_{15,4} = \frac{10!}{2!(10-2)!}*\frac{15!}{4!(15-4)!} = 45*1365 = 61425

The manager can select a team in 61425 ways.

7 0
2 years ago
This problem really confuses me, help?
OLga [1]
So k in the first problem would =1/2
and i guess in the second problem just put k in place of the first space and in the second space put 8 for x. y would then =4. Idk if I did this right, though, I'm honestly a little confused too.
3 0
3 years ago
Read 2 more answers
If the value of third order determinant is 11. Then what is the value of the determinant formed by its cofactors.
nordsb [41]

Answer:

146.41

Step-by-step explanation:

third order determinant = determinant of 3×3 matrix A

given ∣A∣=11

det (cofactor matrix of A) =set (transpare of cofactor amtrix of A) (transpare does not change the det)

=det(adjacent of A)

{det (cofactor matrix of A)}  ^2  = {det (adjacent of A)} ^2

 

(Using for an n×n det (cofactor matrix of A)=det (A)^n−1 )

we get

det (cofactor matrix of A)^2  = {det(A)  ^3−1 }^2

 

=(11)^2×2  = 11^4

 =146.41

5 0
3 years ago
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