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Arte-miy333 [17]
3 years ago
5

Which of these sequences of transformations would not return a shape to its original position?

Mathematics
1 answer:
oksano4ka [1.4K]3 years ago
7 0

Answer:

4.  Rotate 120∘ counterclockwise around center C, then rotate 220∘ counterclockwise around C again.

Step-by-step explanation:

Option 1, 2 and 3 will return a shape back to its original because:

1. 3 units up and 3 units down are direct opposite and will cancel out one another. Hence, the shape will return to its initial position.

2. Reflect over line p, and over p again.

This actions are also direct opposite and also have the same effect as (1)

3. Translate 1 unit to the right and 3 units to the right.

This equates to 4 units to the right and it will cancel out the translation of 4 units to the left.

4. Rotate 120 counter clockwise and another 220 counterclockwise will not make a shape go back to its original position.

Hence:

4 answers the question

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barxatty [35]

Answer:

r = -39

Step-by-step explanation:

So we are trying to solve the equation for r.

-6(2r + 8) = -10(r - 3)

Divide both sides by -2. (This will make distributing much easier.)

3(2r + 8) = 5(r - 3)

Distribute the 3 on the left side and the 5 on the right side,

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Subtract 24 from both sides.

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Subtract 5r from both sides.

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So now we have solve the equation.

I hope you find my answer and explanation to be helpful. Happy studying. :)

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pickupchik [31]

Answer:

Step-by-step explanation:

Perimeter = 4c + 9 + 7c - 5 + 5c + 2 + 5c - 3

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2 years ago
In ΔXYZ, z = 81 cm, ∠Y=139° and ∠Z=6°. Find the length of y, to the nearest 10th of a centimeter.
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Step-by-step explanation:

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Answer:

Option: C is the correct answer.

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Step-by-step explanation:

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It could be seen from the graph.

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