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Mumz [18]
3 years ago
8

Find the sum of the polynomials below.

Mathematics
2 answers:
lisabon 2012 [21]3 years ago
5 0
The answer is C 11x8+5x+2
bazaltina [42]3 years ago
4 0
Tha answer should be choice c
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Find the value of x and y
tiny-mole [99]
<h3>x = 60</h3><h3>y = 60</h3>

x° + 2y° = 180°   ⇒   2y° = 180° - x°

x° = 60°   {three sides of the same lengh, means three angles=60°}

2y° = 180° - 60°

2y° = 120°

y° = 60°

4 0
3 years ago
Write the equation of the line that passes through (7,-4) and (-1,2) in slope-intercept form
s2008m [1.1K]
2-(-4)
--------= 6
-1-7 ---= 3/4
8
y=3/4x
-4=3/4 (7)+b
-4=21/4+b
-4-21/4= -37/4
21/4-21/4=0
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5 0
3 years ago
A man bought certain number of litches
Arlecino [84]

Answer:    The loss is 4%  

Step-by-step explanation:

Lets call litches that are 20 pcs per Rs 100  - litches A

that are 30 pcs per Rs 100- litches B

So a man can buy 2 pcs A per Rs 10

and 3 pcs B per Rs 10

OR

6x  pcs  A per  Rs  30x  

and 6x  pcs  B  per  Rs  20x

Now he gonna sell the 12x  litches  for y Rs

Lets find y from the proportion

12x  cost y

25   cost 100

y/12=100/25

y=48  Rs

So the man bought 6x A + 6x B  for 20x+30x=50 Rs

And then he sold them for 48 Rs

Obviously the man gonna loose the money.

Lets find the losses in %

(50-48)/50*100=200/50=4%

The loss is 4%  

3 0
3 years ago
A tank is full of oil weighing 30 lb/ft3. The tank is an inverted right rectangular pyramid (with the base at the top) with a wi
Gwar [14]

Answer:

Step-by-step explanation:

density of oil, d = 30 lb/ft³

Volume of tank, V = l x w x h = 1 x 2 x 1 = 2 ft³

mass of oil, m = Volume x density of oil = 1 x 30 = 30 lb

Work = m x g x h = 30 x 32 x 3 = 2880 units

5 0
4 years ago
Does dose anyone know how to solve this?
solniwko [45]

Answer:

Width of rectangle = 6 m

Length of rectangle = 11 m

Step-by-step explanation:

Let width of rectangle = w

Length of rectangle = 3w-7

Area of rectangle = 66 m²

We need to find length and width of rectangle

The formula used is: Area=Length \times Width

Putting values and finding w

Area=Length \times Width\\66=(3w-7)(w)\\66=3w^2-7w\\3w^2-7w-66=0\\

Solve using quadratic formula: w=\frac{-b\pm\sqrt{b^2-4ac}}{2a}

We have a=3, b=-7, c=-66

Putting values and finding w

w=\frac{-b\pm\sqrt{b^2-4ac}}{2a}\\w=\frac{-(-7)\pm\sqrt{(7)^2-4(3)(-66)}}{2(3)}\\w=\frac{7\pm\sqrt{49+792}}{6}\\w=\frac{7\pm\sqrt{841}}{6}\\w=\frac{7\pm29}{6}\\w=\frac{7+29}{6}\:,\:w=\frac{7-29}{6}\\w=6, w=-3.6

We get values of w as w=6 and w=-3.6

As we know width cannot be negative, so considering w = 6

So, Width = 6

Length = 3w-7 = 3(6)-7 = 18-7 = 11

So, Width of rectangle = 6 m

Length of rectangle = 11 m

6 0
3 years ago
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