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liubo4ka [24]
3 years ago
14

PLEASE HELP !! ILL GIVE BRAINLIEST !!

Mathematics
2 answers:
jekas [21]3 years ago
8 0

Answer:

1 and 3, 2 and 4, 1 and 2, 3 and 4

5 and 7, 6 and 8, 5 and 6, 7 and 8

Step-by-step explanation:

Nuetrik [128]3 years ago
3 0
Straight angles are two angles that make up a straight line.
1 & 3, 5 & 7, 2 & 4, 6 & 8
and
1 & 2, 3 & 4, 5 & 6, 7 & 8

Please lmk if you have questions.
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Keith_Richards [23]
The answer is 1000001.8
5 0
3 years ago
Find the real zeros 4x²-16x + 2.5x​
Lapatulllka [165]

I am going to assume 2.5x is really 25x (typo).

First formulate the equality

4x^2-16x+25x=0 \\4x^2+9x=0 \\x(4x+9)=0 \\

Now two results emerge.

x_1=0, x_2=-\dfrac{9}{4}.

Hope this helps.

8 0
3 years ago
What is the answer for 7-2x=2(x-4)-1
Vaselesa [24]

Answer:

x=4

Step-by-step explanation:

7-2x=2x-8-1--->distributive property

-4x=-16--->subtraction property

x=4--->division property

7 0
3 years ago
Read 2 more answers
Steven must save $240 to attend summer camp next year. He already saved $30 if you earns $14 per week how many weeks must he sav
Anarel [89]

Answer:

11 2/3

Step-by-step explanation:

240-30

210

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3 0
3 years ago
For what value of k are there two complex solutions to the given quadratic equation (k+1)x²+4kx+2=0.
nlexa [21]

Answer:k\in \left ( \frac{-1}{2},1\right )

Step-by-step explanation:

Given

\left ( k+1\right )x^2+4kx+2=0

For complex  roots Discriminant should be zero

D<0

D=\sqrt{b^2-4ac}

here

D=\sqrt{\left ( 4k\right )^2-4\left ( k+1\right )\left ( 2\right )}

D=\sqrt{16k^2-8k-8}

so 16k^2-8k-8

2k^2-k-1

\left ( 2k+1\right )\left ( k-1\right )

so k\in \left ( \frac{-1}{2},1\right )

3 0
4 years ago
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