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3241004551 [841]
3 years ago
12

Fill in each blank with the correct word to complete the sentence. Multiples that are shared by 2 or more numbers are (blank). T

he lease common multiple is the (Blank) multiple, other than 0, common to sets of multiples
Mathematics
2 answers:
marissa [1.9K]3 years ago
8 0
1= GCF ( greatest common factor)

2- LCD. ( least common denominator)
kondor19780726 [428]3 years ago
7 0
1= GCF or greatest common denominator
2= LCD or least common denominator
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What is the sum of the addition of the two characters 7 + 7 when added​
Over [174]

Answer:196

Step-by-step explanation:

7 + 7 is 14

14 x 14 is 196

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3 years ago
Heathers rabbit has a mass of 5.190 kilograms. Jeff's rabbit has a mass of 5.195 kilograms.Write and inequality statement compar
aleksklad [387]

Answer:

5.190 < 5.195

Step-by-step explanation:

5.195 is bigger than 5.190, so 5.195>5.190

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3 years ago
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Which equation is represented by the graph?
vladimir2022 [97]

Answer: y = -2x - 5

Step-by-step explanation:

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4 years ago
Which function has a vertex on the y-axis? f(x) = (x – 2)2 f(x) = x(x + 2) f(x) = (x – 2)(x + 2) f(x) = (x + 1)(x – 2)
strojnjashka [21]

we know that

If the vertex is on the y-axis, then the x-coordinate of the vertex is equal to zero

we are going to verify the vertex of each one of the functions to determine the solution

Remember that

The equation in vertex form of a vertical parabola is equal to

y=a(x-h)^{2} +k

where

(h,k) is the vertex

if a>0 -------> the parabola open upward (vertex is a minimum)

if a -------> the parabola open downward (vertex is a maximun)

<u>case A)</u> f(x)=(x-2)^{2}

This is a vertical parabola open upward

the vertex is the point (2,0)

therefore

The function f(x)=(x-2)^{2}  does not have a vertex on the y-axis

<u>case B)</u> f(x)=x(x+2)

f(x)=x(x+2)=x^{2}+2x

convert to vertex form

Complete the square. Remember to balance the equation by adding the same constants to each side.

f(x)+1=x^{2}+2x+1

Rewrite as perfect squares

f(x)+1=(x+1)^{2}

f(x)=(x+1)^{2}-1

the vertex is the point (-1,-1)

therefore

The function f(x)=x(x+2) does not have a vertex on the y-axis

<u>case C)</u> f(x)=(x-2)(x+2)

f(x)=(x-2)(x+2)=x^{2}-2^{2}

f(x)=x^{2}-4

the vertex is the point (0,-4)

The x-coordinate of the vertex is equal to zero

therefore

The function f(x)=(x-2)(x+2) has a vertex on the y-axis

<u>case D)</u> f(x)=(x+1)(x-2)

f(x)=(x+1)(x-2)\\ \\f(x)= x^{2}-2x+x-2 \\ \\f(x)= x^{2} -x-2

convert to vertex form

Group terms that contain the same variable, and move the constant to the opposite side of the equation

f(x)+2= x^{2} -x

Complete the square. Remember to balance the equation by adding the same constants to each side.

f(x)+2+0.25= x^{2} -x+0.25

f(x)+2.25= x^{2} -x+0.25

Rewrite as perfect squares

f(x)+2.25= (x-0.50)^{2}

f(x)=(x-0.50)^{2}-2.25

the vertex is the point (0.5,-2.25)

therefore

The function f(x)=(x+1)(x-2) does not have a vertex on the y-axis

<u>the answer is</u>

f(x)=(x-2)(x+2)

6 0
3 years ago
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Answer Are SSS,ASA,AAS,SAS Not enough Information <br> PLEASE HELP ME PLEASE
Leokris [45]

Answer:

1.SAS

2. AAS

3.SAS

4.SSS

5.SSS

6.SSS

Step-by-step explanation:

3 0
3 years ago
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