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2 years ago

17 less than the quantity 5 times a number

Mathematics

2 answers:

amid [387]2 years ago

7 0

17<5×1? I think might be the answer

natita [175]2 years ago

4 0

5diviedby17timesX that's ur answer

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Can the sides of a triangle be in a ratio of: a 3:4:5

victus00 [196]

Yes. In fact $3:4:5$ is a Pythagorean triple or simply right triangle where all sides are in $\mathbb{Z}$ .

Hope this helps.

5 0

3 years ago

Read 2 more answers

Solve 4(4f-9)=-(2-f)

Whitepunk [10]

Answer:

f = $\frac{7}{15}$

Step-by-step explanation:

1. 4(4f - 9) = -(2-f) distribute the negative

2. 4(4f - 9) = -2 + f Distribute the 4

3. 16f - 9 = -2 + f Subtract f on both sides

4. 15f - 9 = -2 Add 9 on both sides

5. 15f = 7 Divide both equations by 15

6. $\frac{15f}{15} = \frac{7}{15}$

f = $\frac{7}{15}$

8 0

3 years ago

Of a squirrel's hidden nuts, for every 5 that get found, there are 3 that do not get found. A squirrel hid 40 nuts all together.

koban [17]

Answer:

15 nuts do not get found.

Step-by-step explanation:

Given that Of a squirrel's hidden nuts, for every 5 that get found, there are 3 that do not get found.

Total number of nuts squirrel had hidden = 40

Proportion of nuts not found to total = 3/(3+5) = 3/8

Hence out of 40, nuts not found =3/8(40) = 15 nuts.

15 nuts would not be found and 25 nuts would be found if squirrel had hidden in total 40 nuts.

This is because the proportion of found:unfound = 5:3

Hence 25:!5 =5:3 satisfies this

15 nuts are not found.

5 0

3 years ago

Read 2 more answers

Mr.Ward runs a lot. He ran 45 minutes each day, 5 days each week , for 16 weeks . In that time, he ran 450 miles. What was his a

Savatey [412]

Answer:

7.5 miles per hour.

Step-by-step explanation:

We have been given that Mr. Ward runs a lot. He ran 45 minutes each day, 5 days each week, for 16 weeks.

First of all, we will find time for that Mr. Ward ran in 16 weeks.

We will multiply 5 by 16 to find number of days for that Mr. Ward ran and then we will multiply the result by 45 minutes to find the time.

$\text{Time for that Mr. Ward ran in 16 weeks}=16\times 5\times 45\text{ minutes}$

$\text{Time for that Mr. Ward ran in 16 weeks}=3600\text{ minutes}$

Now, we will divide 3600 minutes by 60 minutes to convert time into hours as:

$\text{Hours}=\frac{3600}{60}=60$

Now, we will divide 450 miles by 60 hours to find Mr. Ward's average speed as:

$\text{Mr. Ward's average speed}=\frac{450\text{ miles}}{\text{60 hours}}$

$\text{Mr. Ward's average speed}=\frac{7.5\text{ miles}}{\text{ Hour}}$

Therefore, Mr. Ward's average speed in 7.5 miles per hour.

7 0

3 years ago

As instructor grades exams, 30%; term paper, 20%; and final exam, 50%. A student had grades of 75,80, and 85, respectively, for

Leni [432]

Okay, so 75 counts for 30% (exams), 80 counts for 20% (term paper), and 85 counts for 50% (final exam)

So you would multiply 30% by 75, 20% by 80, and 50% by 85. That would be 22.5, 16, and 42.5. Add these numbers up, and put them over the total percentage, 100%. So you would have 81/100. The student's final average is 81%.

6 0

2 years ago