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sukhopar [10]
4 years ago
7

Resolver las siguientes desigualdades 3y<6 -x/2>2 Y+8>9 -3x <15

Mathematics
1 answer:
Crazy boy [7]4 years ago
8 0

Answer:ndbdnd ndbdnd 192

Step-by-step explanation:

BBB as haha

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Step-by-step explanation:

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Hope this helps! :)

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Log10 (x - 9) + log10 x = 1​
Delicious77 [7]

Answer:

\boxed{ \: \boxed{ x  =  10} \: is \: applicable}

Step-by-step explanation:

if \: the \: question \: is \to  \\    \boxed{log_{10}(x - 9) +  log_{10}(x)= 1} \\  then \:  the \: value \: of \:  \boxed{ x }\: can \: be \: gotten \: by \to\\  log_{10} \{ x( x - 9)\} = 1 \\ log_{10}( {x}^{2}  - 9x)  = 1 \\  {10}^{1}  =  {x}^{2}  - 9x \\  {x}^{2}  - 9x = 10 \\  {x}^{2}  - 9x - 10 = 0 \\  {x}^{2}   +  x  -  10x - 10 = 0 \\  x( x +  1)  -  10(x  + 1) = 0 \\ (x  +  1)(x  -  10) = 0 \\ \boxed{\boxed{  x  + 1 = 0 }\: or \: \boxed{ x   - 10 = 0}} \\ \boxed{\boxed{  x  =  - 1 }\: or \: \boxed{ x  =  10}}

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