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sukhopar [10]
3 years ago
7

Resolver las siguientes desigualdades 3y<6 -x/2>2 Y+8>9 -3x <15

Mathematics
1 answer:
Crazy boy [7]3 years ago
8 0

Answer:ndbdnd ndbdnd 192

Step-by-step explanation:

BBB as haha

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What expression is equivalent to -x + 5 - 13 + 12x
zvonat [6]

Answer:

11x - 8

Step-by-step explanation:

If you have x- + 5 - 13 + 12x, all we are doing is combining like terms. First, 5 - 13 = -8. Then, -x + 12x is the same as doing 12x - x. That gives us 11x. The answer would be 11x - 8 when you put -8 and 11x together in the expression.

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3 years ago
The ratio of peanuts to almonds in a snack mix is 24 to 15. Simplify the ratio.
Marianna [84]

Answer:

The simplified ratio would be 8 to 5.

Step-by-step explanation:

We can get the simplified ratio by finding the largest number that both sides can be divided by. In this context, it is the number 3 so we divide both sides by 3 to simplify the ratio.

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2 years ago
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7th grade math help please and thank you
mario62 [17]

Answer:

66+24

Step-by-step explanation:

you just have to add them

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3 years ago
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Pls help meeee Idk how to do this
34kurt
Distribute the x3 to each number. The coefficient stays the same but add exponent (3) onto each x. Final answer is: x to the seventh power plus 8X to the sixth power plus 2X to the fifth power +18 X to the fourth power +9x the third power
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3 years ago
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Which equation has x = –6 as the solution?
olya-2409 [2.1K]

Answer:

The equation 'log Subscript 3 Baseline (negative 2 x minus 3) = 2' i.e. \log _3\left(-2x-3\right)=2  has x = –6 as the solution.

Step-by-step explanation:

<u>Checking the equation</u>

log Subscript 3 Baseline (negative 2 x minus 3) = 2

Writing in algebraic expression

\log _3\left(-2x-3\right)=2

Use the logarithmic definition

\mathrm{If}\:\log _a\left(b\right)=c\:\mathrm{then}\:b=a^c

\log _3\left(-2x-3\right)=2\quad \Rightarrow \quad \:-2x-3=3^2

-2x-3=3^2

-2x-3=9

-2x=12

\mathrm{Divide\:both\:sides\:by\:}-2

\frac{-2x}{-2}=\frac{12}{-2}

x=-6

Therefore, the equation 'log Subscript 3 Baseline (negative 2 x minus 3) = 2' i.e. \log _3\left(-2x-3\right)=2  has x = –6 as the solution.

3 0
3 years ago
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