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lina2011 [118]
3 years ago
10

What is the interquartile range of the data set? {33, 38, 45, 56, 57, 63, 72, 91}

Mathematics
1 answer:
Vikentia [17]3 years ago
8 0
The IQR = 26.
The interquartile range (IQR) is found by subtracting the first quartile from the third quartile (Q3 - Q1 = IQR).

First Quartile (Q1) = 41.5
To find the first quartile, you find the middle value between the minimum value of the set and the set's median. The minimum value of the set is 33, and the median is 56.5 (56 + 57 = 113, 113/2 = 56.5).

Since there are an even number of values in the set, split it in half. Find the median in the lesser half of values: {33, 38, 45, 56}. The two middle values are 38 and 45, which you add together and divide by 2 to get the first quartile. 33 + 38 = 83, 83/2 = 41.5

Third Quartile (Q3) = 67.5
The second half of the data values from when you split the set in half earlier is composed of the numbers {57, 63, 72, 91}. Add 63 and 72 together to get 135 and divide by 2 to find the 3rd Quartile value. 135/2 = 67.5

Interquartile Range: 26
The IQR is found by subtracting Q3 - Q1. You get 67.5 - 41.5 which equals 26. The IQR is 26.
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Question is in the image​
storchak [24]

Answer:

4.

Step-by-step explanation:

y = -2x + 3

-1 = -2(2) + 3

-1 = -4 + 3

-1 = -1

y = x - 3

-1 = 2 - 3

-1 = -1

8 0
3 years ago
How do I find the values of these
skad [1K]
Since the triangles are similar, then 32 = x+7 those two angles are too
solve for "x"

now using proportions   \bf \cfrac{\textit{small triangle}}{\textit{large triangle}}\qquad \cfrac{JK}{18}=\cfrac{12}{12+10}

solve for JK

\bf \cfrac{\textit{small triangle}}{\textit{large triangle}}\qquad \cfrac{12}{12+10}=\cfrac{9}{9+KG}\implies 12(9+KG)=(22)9
\\\\\\
108+9KG=198

solve for KG

the scale factor of the perimeter of both triangles is just the same as the ratio of the sides, or \bf \cfrac{12}{12+10}

3 0
3 years ago
Plss help w this answers are above:)
Andrews [41]
1)6 2)5 3)5 because math is easy hope it helped
8 0
3 years ago
A merchant has coffee worth $20.00 per pound that she wishes to mix with 70 pounds of coffee with​ $90.00 per pound to get a mix
Crank

20x-1000 +4000 = 60x

20x-60x= -4000 +1000

-40x= -3000

x= -3000/-40

75 The mix will be 75 lbs

And $20 coffee will be 75 -50 = 25lbs


6 0
3 years ago
Cody was 165\,\text{cm}165cm165, space, c, m tall on the first day of school this year, which was 10\%10%10, percent taller than
earnstyle [38]
Assume that Cody was x cm tall on his first day at school last year.
Assume that Cody is y cm tall on his first day at school this year.
This year, Cody became 10% taller.
10% is equivalent to 0.1

This can be translated into the following:
y = x + 0.1x 
We are given that y = 165 cm.
Substitute in the equation to get x as follows:
165 = x + 0.1x
165 = 1.1x
x = 150 cm

Based on the above calculations, Cody was 150 cm tall on his first day at school last year.

4 0
3 years ago
Read 2 more answers
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