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lina2011 [118]
2 years ago
10

What is the interquartile range of the data set? {33, 38, 45, 56, 57, 63, 72, 91}

Mathematics
1 answer:
Vikentia [17]2 years ago
8 0
The IQR = 26.
The interquartile range (IQR) is found by subtracting the first quartile from the third quartile (Q3 - Q1 = IQR).

First Quartile (Q1) = 41.5
To find the first quartile, you find the middle value between the minimum value of the set and the set's median. The minimum value of the set is 33, and the median is 56.5 (56 + 57 = 113, 113/2 = 56.5).

Since there are an even number of values in the set, split it in half. Find the median in the lesser half of values: {33, 38, 45, 56}. The two middle values are 38 and 45, which you add together and divide by 2 to get the first quartile. 33 + 38 = 83, 83/2 = 41.5

Third Quartile (Q3) = 67.5
The second half of the data values from when you split the set in half earlier is composed of the numbers {57, 63, 72, 91}. Add 63 and 72 together to get 135 and divide by 2 to find the 3rd Quartile value. 135/2 = 67.5

Interquartile Range: 26
The IQR is found by subtracting Q3 - Q1. You get 67.5 - 41.5 which equals 26. The IQR is 26.
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(25 points!!!!) draw the graph of the area bounded by these inequalities
Stels [109]

Step-by-step explanation:

To draw the graph, follow these steps:

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The three inequalities given form a triangle.

The first equation, y ≤ 2x + 5, has a y-intercept at (0, 5) and a point at (-2, 1).

The second equation, y < -3x + 10, has points at (3, 1) and (2, 4).

Use two points to draw the lines.

After the lines are drawn, determine which side of the line the inequality works on. You can do this by testing points that are not on the line.

I will test each inequality using (0, 1):

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<em>This is correct</em>, so the inequality for y ≤ 2x + 5 will be shaded towards (0, 1).

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<em>This is correct,</em> so the inequality for y < -3x + 10 will be shaded towards (0, 1).

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The end result of this graph is all three inequalities being shaded (inwards).

The solution is a triangle with points at (1, 7), (3.33333, 0), and (-2.5, 0).

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