Answer:
The area of trapezoid is 72 cm²
Step-by-step explanation:
Given : A trapezoid with given dimensions.
We have to find the area of trapezoid ABCD.
Consider the given trapezoid ABCD ,
AB = EF = 8 cm
and CE = FD = 4 cm
Then CD = CE + EF + FD = 4 + 8 + 4 = 16 cm
Thus, Area of trapezoid = ![\frac{1}{2}\cdot \text{(Sum of parallel sides)} \cdot height](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B2%7D%5Ccdot%20%5Ctext%7B%28Sum%20of%20parallel%20sides%29%7D%20%5Ccdot%20height)
here, height = 6 cm
and sum of parallel sides = AB + CD = 16 + 8 = 24 cm
Thus, Area of trapezoid = ![\frac{1}{2}\cdot 24 \cdot 6](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B2%7D%5Ccdot%2024%20%5Ccdot%206)
Simplify, we have,
Area of trapezoid = 72 cm²
Thus, The area of trapezoid is 72 cm²
Answer:
The answer in the procedure
Step-by-step explanation:
we have the right triangle ABC
The pre-image coordinates are
![A(0,0),B(0,3),C(4,0)](https://tex.z-dn.net/?f=A%280%2C0%29%2CB%280%2C3%29%2CC%284%2C0%29)
The transformation to use is the translation
The rule of the translation is
![(x,y)-----> (x+10,y)](https://tex.z-dn.net/?f=%28x%2Cy%29-----%3E%20%28x%2B10%2Cy%29)
That means----> The translation is 10 units to the right
The image coordinates are
Applying the rule of the translation
![A'(0+10,0)=A'(10,0)](https://tex.z-dn.net/?f=A%27%280%2B10%2C0%29%3DA%27%2810%2C0%29)
![B'(0+10,3)=B'(10,3)](https://tex.z-dn.net/?f=B%27%280%2B10%2C3%29%3DB%27%2810%2C3%29)
using a graphing tool
see the attached figure
Answer:
Wanchen has the weaker flavor, no need to freak out.
Step-by-step explanation:
2/3 water for 1/6 lime juice so more water and less lime juice compared to 1/4 water for 1/5 cup of lime juice
Answer:
The number is 7.
Step-by-step explanation:
4n - 7 = 21 Add 7 on both sides
4n = 28 Isolate the variable by dividing 4 on both sides
n= 7
<h3><u><em>
Hope this helps!!!
</em></u></h3><h3><u><em>
Please mark this as brainliest!!!
</em></u></h3><h3><u><em>
Thank You!!!
</em></u></h3><h3><u><em>
:)</em></u></h3>
The radius is r ~ 11m trust me