What is (-3a^2)(-2b^3)(-a^3b^5)
1 answer:
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Answer:
There are no real values of x for point P to belong to the 4 quadrant
Step-by-step explanation:
<u><em>The question in English is</em></u>
To what real values of x does the point P (3x -6, 2x +4) belong to the 4th quadrant?
we know that
A point in the fourth Quadrant has the x-coordinate positive and the y-coordinate negative
we have the point
P (3x-6, 2x+4)
----> inequality A ( x-coordinate must be positive)
---> inequality B ( y-coordinate must be negative)
Solve Inequality A
-----> (2,∞)
Solve Inequality B
----> (-∞,-2)
The solution of the system is
(-∞,-2) ∩ (2,∞)
therefore
The system has no solution
There are no real values of x for point P to belong to the 4 quadrant