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3 years ago

What is the percentage of sugar in the syrup made of 10kg of water and 5kg of sugar? Hi and have a good day :D

Mathematics

2 answers:

arsen [322]3 years ago

8 0

Answer:

33.33%

Step-by-step explanation:

the syrup has a total of 15kg of ingredients, 5kg of it is sugar, so 15/5 which will end as 33.33%

Ksenya-84 [330]3 years ago

7 0

Answer:

33.33%

Step-by-step explanation:

the syrup has a total of 15kg of ingredients, 5kg of it is sugar, so 15/5 which will end as 33.33%

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What is the solution to the equation?

Lisa [10]

$3q + 5 = -2q + 20$

add 2q to both sides.

$5q + 5 = 20$

subtract 5 to both sides.

$5q = 15$

divide 5 to both sides.

$q = \frac{15}{5}$

the answer is: $q = 3$

5 0

3 years ago

The sum of w and 54 is equal to s. Let s = 72. Which equation can be used to find the value of w? A. w – 54 = 72 B. w – 72 = 54

Masteriza [31]

W + 54 = s

w + 54 = 72

Answer: C

Hope this helps!! :)

7 0

3 years ago

Can someone help explain this to me?

o-na [289]

Step-by-step explanation:

A. y-5=-4x+4

y=-4x+4+5

y= -4x +9

(0,9)(9/4,0)

8 0

2 years ago

See attachment below

KatRina [158]

Answer: Third Option

$x=1.469743$

Step-by-step explanation:

We have the following exponential equation

$3^{x+1}=15$

We must solve the equation for the variable x

To clear the variable x apply the $log_3$ function on both sides of the equation

$log_3(3^{x+1})=log_3(15)$

Simplifying we get the following:

$x+1=log_3(15)$

To simplify the expression $log_3 (15)$ we apply the base change property

$log_b(y)=\frac{log(y)}{log(b)}$

This means that:

$log_3 (15)=\frac{log(15)}{log(3)}$

Then:

$x+1=\frac{log(15)}{log(3)}$

$x=\frac{log(15)}{log(3)}-1$

$x=1.469743$

6 0

2 years ago

Evaluate each expression. Click on undefined as needed

Brums [2.3K]

If the 0 is in the numerator, the value is 0
if the 0 is in the denominator, the value is undefined

so 0/8 = 0
and 3/0 = undefined

4 0

3 years ago