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AlekseyPX
3 years ago
6

You volunteer at an animal shelter on the weekends and today is adoption day! At the beginning of the event, you start with 44

Mathematics
1 answer:
Angelina_Jolie [31]3 years ago
8 0

6 cats/kittens were adopted.

Step-by-step explanation:

Given,

Number of cats/kittens at the event = 44

Number of cats/kittens adopted = x

Number of cats/kittens returned = Twice returned as adopted = 2x

New total = 50

We will subtract the adopted and add the returned cats/kittens.

Total cats/kittens at event - adopted + returned = New total

44-x+2x=50\\44+x=50\\x=50-44\\x=6

6 cats/kittens were adopted.

Keywords: expression, variables

Learn more about variables at:

  • brainly.com/question/10666510
  • brainly.com/question/10699220

#LearnwithBrainly

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Sound fruit seller earns a $0.40 profit for each Apple that it sells and a $0.40 profit for each bananas at its cells which expr
Nikolay [14]

Answer:

P= 0.4x+ 0.4y

Step-by-step explanation:

Given data

Profit from apple= $0.4

Profit from banana= $0.4

Let the number of Apples sold be x, and the number of bananas sold be y

and the total profit be P

Hence the expression for the total profit is given as

P= 0.4x+ 0.4y

5 0
3 years ago
Planners of an experiment are evaluating the design of a sphere of radius r that is to be filled with helium (0°c, 1 atm pressur
Vikentia [17]
The solution is:A mole of gas occupies 22.4 L A liter is 1000 cubic centimeters because 1 cubic centimeter = 1 mL
One Helium molecule (essentially one helium atom) has atomic mass 4 g/mol So for every 22400 cubic centimeters of volume, we have 4 grams of helium Density of helium = 4g / 22400 cm^3 = 1g / 5600 cm^3 
Volume of a sphere = (4/3)(pi)r^3 Volume of the outside sphere (the entire sphere) is (4/3)(pi)(R+T)^3 Volume of the inside sphere (the hollow region) is (4/3)(pi)R^3 
The difference for the volume of silver. (4/3)(pi)(R+T)^3 - (4/3)(pi)R^3 = (4/3)(pi)(3R^2T + 3RT^2 + T^3) 
The density of silver is 10.5g/cm^3 
So the mass of the silver is computed by:10.5*(4/3)(pi)(3R^2T + 3RT^2 + T^3) = (14*pi)(3R^2T + 3RT^2 + T^3) = (14pi)T(3R^2 + 3RT + T^2) 

Now for the mass of helium: volume x density = (4/3)(pi)R^3 (1/5600) = (pi/4200)R^3 

Set the two masses equal: (pi/4200)R^3 = (14pi)T(3R^2 + 3RT + T^2) R^3 = 58800*T(3R^2 + 3RT + T^2) R / T = 58800*(3R^2 + 3RT + T^2) / R^2 = 58800*( 3+T/R^2+(T/R)^2) 
then solve for xx = T / R 1/x = 58800*( 3+x/R+x^2) 1/58800 = x (3 + x/R + x^2) 1/58800 = 3x + x^3 x^3 + 3x - 1/58800= 0 x = ~ 5.66893x10^(-6)
6 0
3 years ago
PLEASE HELP!!
I am Lyosha [343]
36 + 18 = 54

(1) 18/54 = 1/3 = 33%

43 + 24 = 67

(2) 24/67 = 36%




I hope these are right
3 0
3 years ago
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Jason wants to add a fence to his yard to make it the shape of a rectangle. What is the measure of angle MKJ in the portion of t
alex41 [277]

Answer:

\angle MKJ  = 34

Step-by-step explanation:

Given

\angle LKJ = 124

Required

Find \angle MKJ

From the attachment:

The measure of \angle MKJ is calculated using the following expression:

\angle MKJ  + \angle LKM = \angle LKJ

Where

\angle LKM = 90 -- right-angled.

The expression becomes

\angle MKJ  + 90 = 124

\angle MKJ  = 124 - 90

\angle MKJ  = 34

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3 years ago
Solve and graph and plot this on the line
alexira [117]
X less than or equal to (< with the line underneath) -3 or x>0
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