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AlekseyPX
4 years ago
6

You volunteer at an animal shelter on the weekends and today is adoption day! At the beginning of the event, you start with 44

Mathematics
1 answer:
Angelina_Jolie [31]4 years ago
8 0

6 cats/kittens were adopted.

Step-by-step explanation:

Given,

Number of cats/kittens at the event = 44

Number of cats/kittens adopted = x

Number of cats/kittens returned = Twice returned as adopted = 2x

New total = 50

We will subtract the adopted and add the returned cats/kittens.

Total cats/kittens at event - adopted + returned = New total

44-x+2x=50\\44+x=50\\x=50-44\\x=6

6 cats/kittens were adopted.

Keywords: expression, variables

Learn more about variables at:

  • brainly.com/question/10666510
  • brainly.com/question/10699220

#LearnwithBrainly

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Step-by-step explanation:

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3 years ago
The following table represents a grouped frequency distribution of the number of hours spent on the computer per week for 59 stu
Marysya12 [62]

The value of the lower class limit of the 3rd class is; 11.0

<h3>What is the lower class Interval?</h3>

The lower class limit is lowest value of that class interval while upper class limit is highest value of that class interval.

Hours Number of Students

0.0–5.4         12

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8 0
1 year ago
The perimeter of a rectangle is 72 cm. The length is 3 more than twice the width What
solmaris [256]
<h3><u>Solution</u></h3>

<u>Given </u><u>:</u><u>-</u>

  • Perimeter of rectangle = 72 cm
  • The length is 3 more than twice the width.

<u>F</u><u>i</u><u>n</u><u>d</u><u> </u><u>:</u><u>-</u>

  • Dimensions of rectangle
<h3 /><h3><u>Explantion</u></h3>

<u>Using </u><u>Formula</u>

\boxed{\underline{\tt{\red{\:(perimeter_{rectang}\:=\:2\times (Length+Width)}}}}

<u>Let,</u>

  • Length of Rectangle = x cm
  • Breadth of Rectangle = y cm

<u>According</u><u> to</u><u> question</u><u>,</u>

==> perimeter of Rectangle = 72

==> 2(x+y) = 72

==> x + y = 72/2

==> x + y = 36_________________(1)

<u>Again,</u>

==> x = 2y + 3

==> x - 2y = 3__________________(2)

<u>Subtract</u><u> </u><u>equ(</u><u>1</u><u>)</u><u> </u><u>&</u><u> </u><u>equ(</u><u>2</u><u>)</u>

==> y + 2y = 36 - 3

==> 3y = 33

==> y = 33/3

==> y = 11

<u>keep </u><u>in </u><u>equ(</u><u>1</u><u>)</u>

==> x - 2×11 = 3

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<h3><u>Hence</u></h3>

  • <u>Length</u><u> of</u><u> </u><u>Rectangle</u><u> </u><u>=</u><u> </u><u>2</u><u>5</u><u> </u><u>cm</u>
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<h3 />

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Answer:

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