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mash [69]
3 years ago
14

Can anyone help me here this is a mastery test by the way. Too tired to type it out so I put a photo.

Mathematics
1 answer:
meriva3 years ago
8 0

Answer:

1st Question is 22r4

2nd Question is 22r16

3rd Question is 11r11

4th Question is 11r30

Step-by-step explanation:

Hope this helps. I'll give you my energy.

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which equation represents this sentence? one-half the sum of a number and four is three less than the quotient of five and the n
Elena L [17]

a.) 1/2n 4=3−5/n b.) 1/2(n 4)=5/n−3 c.) 1/2(n 4)=3−5/n d.) 1/2n 4=5/n−3

Let's assume the number be n.

So, sum of number and four can be written as n+4.

Now one-half of n+4 will be \frac{1}{2} (n+4).

Quotient of five and the number can be written as \frac{5}{n}.

Now three less \frac{5}{n} can be written as \frac{5}{n} -3.

So, one-half the sum of a number and four is three less than the quotient of five and the number can be converted into equation as follows:

\frac{1}{2} (n+4)=\frac{5}{n}-3

So, b is the correct choice.

6 0
3 years ago
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If you can answer 5 questions in an hour, how many questions can you complete in 3 hours? HINT: Use the proportion 5 questions :
Stella [2.4K]

Answer:

15

Step-by-step explanation:

1 hr: 5

2 hr: 10

3 hr: 15

3 0
3 years ago
7 earn 5 coins
Sergio039 [100]
The answer is 9 cubic units
5 0
3 years ago
Enter the values for m, n, and p that complete the difference:
inessss [21]

Answer:

p = 2

n = 14

m = 3

Step-by-step explanation:

In order to be able combine (either add or subtract) rational expressions we need to write them with a common (similar) denominator. For that reason we first find the Least Common Denominator of both fractions, that way understanding how to express the two fractions using equivalent fractions with like denominator that can be combined.

We see that the denominator of the first fraction contains the factor "x", therefore "x" has to be a factor of that least common denominator.

We also see that the second fraction  contains "2" as a factor, therefore 2 has to be a factor as well for our Least Common Denominator (LCD)

So the LCD we need is the product: 2*x which we write as 2x.

Now we write the first fraction as an equivalent one but with denominator "2x" by multiplying top and bottom by 2 (and thus not changing the actual value of the fraction): \frac{7}{x} =\frac{7*2}{x*2} =\frac{14}{2x}

Next we do the same with the second fraction, this time multiplying top and bottom by the factor "x":

\frac{3}{2} =\frac{3x}{2x}

Now that both fractions are written showing the same denominator , we can combine them as indicated:

\frac{7}{x} -\frac{3}{2} =\frac{14}{2x} -\frac{3x}{2x} =\frac{14-3x}{2x}

This expression gives as then the values for the requested coefficients.

p = 2

n = 14

m = 3

5 0
3 years ago
Read 2 more answers
What is not a problem modular division is used for?
Oksana_A [137]

Answer:

First let's define what modular arithmetic is, what would come is an arithmetic system for equivalence classes of whole numbers called congruence classes.

Now, the modular division is the division in modular arithmetic.

Answering the question, a modular division problem like ordinary arithmetic is not used, division by 0 is undefined. For example, 6/0 is not allowed. In modular arithmetic, not only 6/0 is not allowed, but 6/12 under module 6 is also not allowed. The reason is that 12 is congruent with 0 when the module is 6.

4 0
3 years ago
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