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dimaraw [331]
3 years ago
14

Without solving, determine the number of solutions for this system. What does the graph of the system look like?

Mathematics
2 answers:
cupoosta [38]3 years ago
5 0

Rewriting each equation in slope-intercept form, you have

... y = (3/2)x -5/4

... y = (3/2)x - 5/6

These lines have the same slope, but different intercepts. The appropriate description is ...

... A) no solution; parallel lines

likoan [24]3 years ago
4 0

Answer:Correct

no solution; parallel lines

You can determine the number of solutions for the system without solving by rewriting the equations in standard form and simplifying.

Rewrite the equations in standard form:

6x - 4y = 5

9x - 6y = 5

Factor out the GCF for each equation:

2(3x - 2y) = 5

3(3x - 2y) = 5

Simplify:

3x - 2y =  

5

2

3x - 2y =  

5

3

3x -2y cannot equal both  

5

2

and  

5

3

. Therefore the system doesn't have any solutions.

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You roll a red-sided die and a white-sided die. Find the probability. P(red is less than 3 and white is less than 3) Simplify th
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1 on 3

Step-by-step explanation:

The red dice has 6 faces. The number you have to obtain is less than 3. So your answers must be 1 and 2. The numbers 1 and 2 are two solutions out of six. Now the same goes with the white dice. Two solutions out of six. You combine them and obtain 4 on 12. Then, you reduce the answer in minimal terms and finally obtain 1 on 3.

4 0
3 years ago
when a pen is sold at a discount of 15%, there is a gain of Rs 10. but if it is sold at 25% discount, there is a loss of Rs 2. f
LenaWriter [7]

Answer:

Rs 120.  

Step-by-step explanation:

10=0.85SP-CP; CP+10=0.85SP; SP=[CP+10]/0.85 Eq 1. Let SP= Selling Price and CP= Cost Price

-2 =0.75SP-CP; 0.75SP=C-2; SP=[CP-2]/0.75 Eq 2

[CP+10]/0.85=[CP-2]/0.75 : SP of Eq 1=SP of Eq 2

0.75[CP+10]=0.85[CP-2]

0.75CP+7.5=0.85CP-1.7

0.85CP-0.75CP=-1.7–7.5=9.2

0.10CP=9.2; CP=9.2/0.10

CP=Rs 92 Cost Price of pen

10=0.85SP-92; 0.85SP=92+10=102; SP=102/0.85=Rs 120 Marked Price of pen (answer)

From Eq2: -2=0.75SP-CP; 0.75SP=CP-2=92–2=90; SP=90/0.75=Rs120; -2=0.75(120)-CP; CP-2=0.75(120); CP-2=90; CP=90+2=Rs 92

Set CP of Eq 1=CP of Eq 2:

CP=0.85SP-10 from Eq 1; CP=0.75SP+2 from Eq 2;

0.85SP-10=0.75SP+2; 0.85SP-0.75SP=10+2=12

0.10SP=12; SP=12/0.10=Rs120 is the Marked Price(answer)

Normally, the Selling Price is the marked price. The seller will not disclose the Cost Price because it is the price when the item was acquired or procured, otherwise the buyer will ask for more discounts and based his buying price from the Cost Price if it is known. The calculated SP and CP satisfy both Eq 1 and Eq 2. Both Eq 1 and Eq 2 satisfy the given conditions of the problem above.

8 0
2 years ago
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