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2 years ago

a student needs to fill a tank with 9 liters of waters how many 1/3 liters of water will it take to fill the tank

Mathematics

2 answers:

xeze [42]2 years ago

8 0

Answer:

Step-by-step explanation:

1= 1/3x3

3x9=27

laiz [17]2 years ago

7 0

It will take 27 containers of 1/3 liter to fill the tank.

Since you need 3 containers of 1/3 to have a full liter, and 9 liters for the tank, 9*3=27.

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What are the solutions to the following system? StartLayout Enlarged left-brace 1st row negative 2 x squared + y = negative 5 2n

Yakvenalex [24]

Answer:

$(\sqrt{2},-1),(-\sqrt{2},-1)$

(StartRoot 2 EndRoot, negative 1) and (negative StartRoot 2 EndRoot, negative 1)

Step-by-step explanation:

we have

$-2x^{2} +y=-5$ ----> equation A

$y=-3x^{2} +5$ -----> equation B

solve by substitution

substitute equation B in equation A

$-2x^{2} +(-3x^{2} +5)=-5$

solve for x

$-5x^{2} +5=-5$

$-5x^{2}=-10$

$x^{2}=2$

$x=\pm\sqrt{2}$

<em>Find the value of y</em>

$y=-3x^{2} +5$

For $x=\sqrt{2}$ ----> $y=-3(\sqrt{2})^{2} +5=-1$

For $x=-\sqrt{2}$ ----> $y=-3(-\sqrt{2})^{2} +5=-1$

therefore

The solutions are

$(\sqrt{2},-1),(-\sqrt{2},-1)$

(StartRoot 2 EndRoot, negative 1) and (negative StartRoot 2 EndRoot, negative 1)

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3 years ago

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Whitepunk [10]

Answer:

Step-by-step explanation:

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3 years ago

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Simplify square root 58 over square root 2

pantera1 [17]

Answer:

5.38516482 or 5.4 or 5

Step-by-step explanation:

The square root of 58 is 7.61577311 and the square root of 2 is 1.41421356.

Divide those 2 numbers and you get 5.38516482 or 5.4 or 5

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3 years ago

What is the length of BC

hodyreva [135]

I'm pretty sure your answer is 17

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What is the simplified form of the quantity of x plus 7, all over the quantity of 6 − the quantity of x plus 5, all over the qua

vlabodo [156]

For this case we must simplify the following expression:

$\frac {\frac {x + 7} {6- (x + 5)}} {x + 3}$

We must apply double C:

$\frac {(x + 7) (x + 3)} {6- (x + 5)} =$

We apply distributive property in the numerator:

$\frac {x ^ 2 + 3x + 7x + 21} {6- (x + 5)} =\\\frac {x ^ 2 + 10x + 21} {6- (x + 5)} =$

In the denominator we have by law of signs:

$- * + = -\\\frac {x ^ 2 + 10x + 21} {6-x-5} =$

Different signs are subtracted and the sign of the major is placed:

$\frac {x ^ 2 + 10x + 21} {- x + 1}$

ANswer:

$\frac {x ^ 2 + 10x + 21} {- x + 1}$

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