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kodGreya [7K]
3 years ago
8

Mr. Campbell was travelled 80 miles in 2 hours. What was his average speed?

Mathematics
1 answer:
Mamont248 [21]3 years ago
4 0
His average speed is 40mph you get your answer by dividing 80 by 2, or or you could do what is half of 80 which is 40. So Mr.Campbell average speed is 40mph
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Write 500m out of 4km as a percentage​
xz_007 [3.2K]

Answer:

∴ 5.5% is 55 m of 1 km.

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6 0
3 years ago
Olivia has $150 in her savings account. She will save and deposit $40 each week. What inequality show how many weeks it will tak
taurus [48]

Answer:

40x+150>=400 i think

Step-by-step explanation:

40x+150>=400

40x>=250

x=6.25

7 0
3 years ago
The circle graph shows the result of a survey. In what way is this graph misleading? Explain.
Rashid [163]

Step-by-step explanation:

because the total sum of each percent is 90%

and it must be 100% as it is a full circle

6 0
3 years ago
If n is a positive integer, how many 5-tuples of integers from 1 through n can be formed in which the elements of the 5-tuple ar
sleet_krkn [62]

This question is incomplete, the complete question is;

If n is a positive integer, how many 5-tuples of integers from 1 through n can be formed in which the elements of the 5-tuple are written in increasing order but are not necessarily distinct.

In other words, how many 5-tuples of integers  ( h, i , j , m ), are there with  n ≥ h ≥ i ≥ j ≥ k ≥ m ≥ 1 ?

Answer:

the number of 5-tuples of integers from 1 through n that can be formed is [ n( n+1 ) ( n+2 ) ( n+3 ) ( n+4 ) ] / 120

Step-by-step explanation:

Given the data in the question;

Any quintuple ( h, i , j , m ), with n ≥ h ≥ i ≥ j ≥ k ≥ m ≥ 1

this can be represented as a string of ( n-1 ) vertical bars and 5 crosses.

So the positions of the crosses will indicate which 5 integers from 1 to n are indicated in the n-tuple'

Hence, the number of such quintuple is the same as the number of strings of ( n-1 ) vertical bars and 5 crosses such as;

\left[\begin{array}{ccccc}5&+&n&-&1\\&&5\\\end{array}\right] = \left[\begin{array}{ccc}n&+&4\\&5&\\\end{array}\right]

= [( n + 4 )! ] / [ 5!( n + 4 - 5 )! ]

= [( n + 4 )!] / [ 5!( n-1 )! ]

= [ n( n+1 ) ( n+2 ) ( n+3 ) ( n+4 ) ] / 120

Therefore, the number of 5-tuples of integers from 1 through n that can be formed is [ n( n+1 ) ( n+2 ) ( n+3 ) ( n+4 ) ] / 120

4 0
3 years ago
The length of a rectangle is 5 inches more than the width. The area is 33 square inches. Find the length and width . Round to th
EleoNora [17]

Answer:

the length and width . Round to the nearest tenth are 8.8 inches and 3.8 inches respectively.

Step-by-step explanation:

The area A of a rectangle is the product of the length L and width W. This may be expressed mathematically as

A = L * W

As such, given that the length is 5 inches more than the width,

L = W + 5

33 = W(W + 5)

W² + 5W  - 33 = 0

Using the formula method which states that

s = -b±√(b²-4ac)/2a

W = -5 ± √5² - 4(1)(-33)/2

= -5 ± 12.53/2

= 7.53/2 (since length cannot be negative)

= 3.755 inches

L = 3.755 + 5

= 8.755 inches

6 0
3 years ago
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