Answer:
Area = 228 m²
Perimeter = 60 m
Step-by-step explanation:
The figure given shows a rectangle that has a cut triangular portion.
✔️Area of the figure = area of rectangle - area of the triangular cut portion
= L*W + ½*bh
Where,
L = 20 m
W = 12 m
b = 20 - (8 + 8) = 4 m
h = 6 m
Plug in the values
Area = 20*12 - ½*4*6
Area = 240 - 12
Area = 228 m²
✔️Perimeter = perimeter of rectangle - base of the triangular cut portion
= 2(L + W) - b
L = 20 m
W = 12 m
b = b = 20 - (8 + 8) = 4 m
Plug in the values
Perimeter = 2(20 + 12) - 4
= 2(32) - 4
= 64 - 4
Perimeter = 60 m
the upper quartile is 160
Hello!
To solve algebraic equation, we will need to use the acronym SADMEP.
SADMEP is similar to PEMDAS, but it is strictly used for solving algebraic equations. Expanded, it is subtract, addition, division, multiplication, exponents, and then parentheses.
Looking at SADMEP, we see that subtract/addition comes first, then division/multiplication, and then exponents/parentheses.
In our equation, our goal is to isolate the variable, "x". Since we have two constants, -3 and 11, and -3 is on the side with the variable, we can add -3 to both sides of the equation first.
Therefore, the first operation needed to solve the equation is addition.
<u>Answer:</u>
- The solution to the problem is -38.
<u>Step-by-step explanation:</u>
- -(6m + 8) = 4(17 - m)
- => -6m - 8 = 68 - 4m
- => -6m + 4m = 68 + 8
- => -2m = 76
- => m = 76/-2
- => m = -38
Hence, <u>the solution to the problem is -38.</u>
Hoped this helped.
