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arlik [135]
3 years ago
12

What is the upper quartile?

Mathematics
1 answer:
RoseWind [281]3 years ago
5 0
the upper quartile is 160
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Why is the vertex of vertex form y=a(x-h)^2+k (h,k) rather than (-h,k)? If that was y=2(x-5)^2+6, the vertex would be at (5,6) w
Sindrei [870]

9514 1404 393

Answer:

  (5, 6) is (h, k)

Step-by-step explanation:

Vertex form is an instance of the transformation of parent function f(x) = x². It is vertically scaled by a factor of 'a', and translated so the vertex is point (h, k). That is, the transformed vertex is h units right and k units up from that of the parent function (0, 0).

Parent:

  f(x) = x^2

Transformed:

  f(x) = a(x -h)^2 +k

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When you compare the form to your specific instance, you need to pay attention to what it is that you're comparing. As the attachment shows, ...

  • a = 2
  • -h = -5   ⇒   h = 5
  • k = 6

Hence the vertex is (h, k) = (5, 6). The second attachment shows this on a graph.

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Wouldn’t it be 110???
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How many thousands are in 5000 ones
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There are 5. In 5000, there are 5 thousandths.
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If angle ec is a bisector then angles Bec and ced are the same making them both 4x+1. we know a line segment equals 180°. so if we take the 11x-12 and add it to 2(4x+1) we end up with 19x-10=180. you add 10 to both sides and get 19x=190 then you divide by both sides. you'll end up with x=10. you plug In the 10 with aeb and aec and add them together to get 139°. if you're looking for the equation, it's 15x-11.
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What are the leading coefficient and degree of the polynomial? 3u-5u^6+9u^3.<br><br> HELP!
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Answer:

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Step-by-step explanation:

Since 6 is the highest power, it is the degree, and so we also take the coefficient of that term.

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