B. The electron transport chain is the final step on cellular respiration in which 32 ATP is made and water
all the thymine pairs with adenine, therefore there is the same number of adenine and thymine bases and the same percentage
so we have 28%thymine and 28% adenine
100-28-28=44% left
this 44% is guanine and cytosine. All of the guanine pairs with cytosine and all of the cytosine pairs with guanine so we have 44/2=22% cytosine and guanine
composition:
28%adenine
28%thymine
22%guanine
22%cytosine
Explanation: the movement of organelles and other substances within cells. Endoplasmic reticulum
Let a be Q, all which is homozygous recessive = Q∧2
A = p, AA which is homozygous recessive = Q∧2
2pq = heterozygous
It is derived from p+ q = 1
All those in a population which is Q = 20%
All A in the population (p) = 80%
Now that the disease is homozygous recessive therefore,
aa = qq or q × q = 0.20 × 2 = 4%
Then the answer is 4%.
Answer: no
Reason: because
