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Alona [7]
3 years ago
7

Jayne stopped to get gas before going on a road trip. The tank already had 4 gallons of gas in it. Which best describes why the

graph relating the total amount of gasoline in the tank, y, to the number of gallons that she added to it, x, will be continuous or discrete? The graph will be continuous because the amount of gas that she added to the tank does not need to be an integer amount. The graph will be continuous because we are not told a maximum value for the amount of gas. The graph will be discrete because there are already exactly 4 gallons of gas in the tank, so to fill it up will take a whole number of gallons of gas. The graph will be discrete because there is an end to the amount of gas she can use, as the tank will be completely full at some point.

Mathematics
2 answers:
bagirrra123 [75]3 years ago
6 0

Jayne stopped to get gas before going on a road trip. The tank already had 4 gallons of gas in it. Which best describes why the graph relating the total amount of gasoline in the tank, y, to the number of gallons that she added to it, x, will be continuous or discrete?


The graph will be continuous because the amount of gas that she added to the tank does not need to be an integer amount.

The graph will be continuous because we are not told a maximum value for the amount of gas.

The graph will be discrete because there are already exactly 4 gallons of gas in the tank, so to fill it up will take a whole number of gallons of gas.

The graph will be discrete because there is an end to the amount of gas she can use, as the tank will be completely full at some point.

Musya8 [376]3 years ago
3 0

the tank holds 4 gallons


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vazorg [7]

Answer:

The 50th term is 288.

Step-by-step explanation:

A sequence that each term is related with the prior by a sum of a constant ratio is called a arithmetic progression, the sequence in this problem is one of those. In order to calculate the nth term of a setence like that we need to use the following formula:

an = a1 + (n-1)*r

Where an is the nth term, a1 is the first term, n is the position of the term in the sequence and r is the ratio between the numbers. In this case:

a50 = -6 + (50 - 1)*6

a50 = -6 + 49*6

a50 = -6 + 294

a50 = 288

The 50th term is 288.

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Step-by-step explanation:

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3 years ago
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Stephanie is making 1 1/2 batches of cookies using 2 3/4 cup sugar. How much sugar total?()
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Answer:

33/8 or 4 1/8 simplified.

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3 years ago
5 more than the quotient of a number and 8 is 42
Zepler [3.9K]

Answer:

<u>The number is 296.</u>

Step-by-step explanation:

Let's call "x" to the number we are looking for.

Now, the problem states that "5 more than the quotient of a number and 8 is 42". This means that this number is being divided by 8, it's also being additioned 5 and the final result is 42. Therefore, the expression of this operations on this number is the following:

\frac{x}{8}+5=42. Let's solve the equation to find x.

1. Write the expression.

\frac{x}{8}+5=42

2. Substract 5 from both sides and simplify.

\frac{x}{8}+5-5=42-5\\\\\frac{x}{8}=37\\\\

3. Multiply 8 on both sides and simplify.

8*\frac{x}{8}=37*8\\\\x=296

<u>We have found our number, it's 296!</u>

3 0
2 years ago
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From a large number of actuarial exam scores, a random sample of scores is selected, and it is found that of these are passing s
Mnenie [13.5K]

<u>Supposing 60 out of 100 scores are passing scores</u>, the 95% confidence interval for the proportion of all scores that are passing is (0.5, 0.7).

  • The lower limit is 0.5.
  • The upper limit is 0.7.

In a sample with a number n of people surveyed with a probability of a success of \pi, and a confidence level of \alpha, we have the following confidence interval of proportions.

\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}

In which

z is the z-score that has a p-value of \frac{1+\alpha}{2}.

60 out of 100 scores are passing scores, hence n = 100, \pi = \frac{60}{100} = 0.6

95% confidence level

So \alpha = 0.95, z is the value of Z that has a p-value of \frac{1+0.95}{2} = 0.975, so z = 1.96.

The lower limit of this interval is:

\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.6 - 1.96\sqrt{\frac{0.6(0.4)}{100}} = 0.5

The upper limit of this interval is:

\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.6 + 1.96\sqrt{\frac{0.6(0.4)}{100}} = 0.7

The 95% confidence interval for the proportion of all scores that are passing is (0.5, 0.7).

  • The lower limit is 0.5.
  • The upper limit is 0.7.

A similar problem is given at brainly.com/question/16807970

5 0
3 years ago
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