Hey there! :)
Answer:
a. b = y - mx
b. x = y - b /m
c. t = I/ pr
d. t = A - p/pr
Step-by-step explanation:
a. y = mx + b (for b)
Isolate the b variable by subtracting both sides by mx:
y - mx = b.
Therefore:
b = y - mx.
b. y = mx + b (for x)
Subtract 'b' from both sides:
y - b = mx
Divide 'm' from both sides:
y - b / m = x
c. I = prt
Divide both sides by pr:
I /pr = t.
d. A = p + prt
Subtract p from both sides:
A - p = prt
Divide both sides by pr:
A - p / pr = t
Diana had chocolate, and ate some, leaving 0.75 of it for Sarah.
Sarah ate 18.5 grams of it and return the rest to Diana, which was 65% of the original chococate.
how much chocolate did Diana have at the beginning?
and the solution is:
0.75x-18.50=0.65x
0.75x-0.65x=18.50
0.1x=18.50
x=185
so Diana had 185 grams of chocolate.
So actually you have 100%
401 + 239 + 306 = 1000
Now 293 from the 1000 is favored,
So in pregnant is 293/1000 = 0.293
That’s also the probability to random person is favor (or 29.3% chance)
Answer:
1 2/8 and 1 1/15
Step-by-step explanation:
10/8 is equal to 1 and 2/8
16/15 is equal to 1 and 1/15
You should divide 87 by 114 for the precent of people. 76% with an margin either way is between 80% and 72%.