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4 years ago

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(09.01 LC) Look at the figure below: A circle is shown with the center O. OP is a segment joining center O to a point P on the c

ircle. MN is a line touching the cir Which is the tangent to the circle? (6 points) Segment OP Line ST Line MN Segment QR

2 answers:

telo118 [61]4 years ago

8 0

Line MN is the tangent

never [62]4 years ago

6 0

Answer:

Line MN is the answer

Step-by-step explanation:

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Determine if the table shows a linear or an exponential function

____ [38]

Answer:

<em>The table shows an exponential function</em>

Step-by-step explanation:

<u>Linear vs Exponential Functions</u>

A linear function is written as:

$y=mx+b$

where m and b are constants.

If a table contains a linear function, then for each pair of ordered pairs (x1,y1) and (x2,y2), the value of m must be constant.

The slope can be calculated as:

$\displaystyle m=\frac{y_2-y_1}{x_2-x_1}$

An exponential function is written as:

$y=y_o.r^x$

Where r is the ratio and yo is a constant.

If a table contains an exponential function, for two ordered pairs (x1,y1) and (x2,y2), the value of r must be constant.

The ratio can be calculated as:

$\displaystyle r=\sqrt[x2-x1]{\frac{y2}{y1}}$

Calculate the slope for (0,4) and (1,2):

$\displaystyle m=\frac{2-4}{1-0}=-2$

Calculate the slope for (1,2) and (2,1):

$\displaystyle m=\frac{1-2}{2-1}=-1$

Since the slope is not the same, the function is not linear.

Now calculate the ratio for (0,4) and (1,2)

$\displaystyle r=\sqrt[1-0]{\frac{1}{2}}$

The radical of index 1 is simply equal to its argument:

$\displaystyle r=\frac{1}{2}$

Now calculate the ratio for (0,4) and (2,1)

$\displaystyle r=\sqrt[2-0]{\frac{1}{4}}$

$\displaystyle r=\sqrt{\frac{1}{4}}$

$\displaystyle r=\frac{1}{2}$

Testing other points we'll find the same ratio, thus the table is an exponential function

4 0

3 years ago

Read 2 more answers

Can someone help? At least solve one that you might know, explain if you can.

Sladkaya [172]

The awnser for question 5 is 4/6

7 0

3 years ago

Let f(x) = x + 8 and g(x) = x2 − 6x − 7. find f(g(2)). −7 −3 10 33 open study

Ray Of Light [21]

F(g(2))

g(x) = x^2 - 6x - 7
g(2) = 2^2 - 6(2) - 7
g(2) = 4 - 12 - 7
g(2) = -15

f(x) = x + 8
f(g(2) = f(-15) = -15 + 8 = -7 <==

ur answer is -7

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4 years ago

Join my zoom anyone codess one the screeen join

Vesna [10]

Answer:

I can but why?

Step-by-step explanation:

7 0

4 years ago

Read 2 more answers

Here is an easy puzzle:

galina1969 [7]

The answer is
date
1 2 3 4 5 31
r1 r2 r3 r4 r5 . . . r31
1gm 2gms 3<span>gms 4gms 5gms . . . 31gms

r1+r2+ .... +r31= 31(31+1) /2=496gms (31 rings)

he only made 5 rings

31 rings----------> 496 gms
5 rings ------------> ? = 5 x496 / 31=80 gms

</span><span> the weights of those 5 rings was 80 gms</span>

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4 years ago