Three thousand six hundred fifty-one; 3000+600+50+1
Answer:
48 minutes
Step-by-step explanation:
Given that:
Time taken by Janet = 3 hours
Janet's rate = 1/3 job / hour
Time taken by Garry = 2 hours
Garry's rate = 1/2
Rate of working together :
1/3 + 1/2 = (2 + 3) /6 = 5/6 job/hour
If Janet works for one hour before Garry joins ;
1/3 of the job has been done by Janet
1 - 1/3 = 2/3 of the job left
Hence to finish the job together, it will take :
Fraction of JOB left ÷ rate of working together
(2/3 ÷ 5/6)
= 2 /3 * 6/5
= 12 / 15
= 4 / 5 hours
To minutes
(4/5) * 60
= 240/5
= 48 minutes
=Y2-10Y
We move all terms to the left:
-(Y2-10Y)=0
We add all the numbers together, and all the variables
-(+Y^2-10Y)=0
We get rid of parentheses
-Y^2+10Y=0
We add all the numbers together, and all the variables
-1Y^2+10Y=0
a = -1; b = 10; c = 0;
Δ = b2-4ac
Δ = 102-4·(-1)·0
Δ = 100
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
Y1=−b−Δ√2aY2=−b+Δ√2a
Δ‾‾√=100‾‾‾‾√=10
Y1=−b−Δ√2a=−(10)−102∗−1=−20−2=+10
Y2=−b+Δ√2a=−(10)+102∗−1=0−2=0
