Answer:
yes , 33^2 + 56^2 = 65^2 and obtuse
Step-by-step explanation:
<h2><u>Question 3</u></h2>
make use of the Pythagoras theorem
which is :
c^2 = a^2 + b^2
where c is the hypotenuse.
now put the values in the equation
65^2 = 56^2 + 33 ^2
the answer is :
<u>yes , 33^2 + 56^2 = 65^2</u>
<u></u>
<h2><u>Question 4</u></h2>
<u />
note if :
c^2 = a^2 + b^2 ----------- right
c^2 < a^2 + b^2------------ acute
c^2 > a^2 + b^2------------- obtuse
hence :
16 + 30 > 38
therefore its : <u>obtuse </u>
I think is
4 x + 2y
256x + 16y
Step-by-step explanation:
dy/dx
= d/dx [x / (1 - x²)]
= [(1 - x²)(1) - (x)(-2x)] / (1 - x²)²
= (1 + x²) / (1 - x²)².
When dy/dx = 1, (1 + x²) / (1 - x²)² = 1.
=> 1 + x² = 1 - x²
=> 2x² = 0, x = 0.
Also when x = 0, y = (0) / [1 - (0)²] = 0.
Hence the coodinates is (0, 0).
I believe its 10-6i im pretty sure
one paper sheet = 500 / 305 cents
134 * 13 = 1742
500 / 305 = 1.64 cents
1.64 * 1742 = $28.55
