X=width of a coccer pitch
2x-20=length of a soccer pitch
Area (rectangule)=length x width
We suggest this equation:
x(2x-20)=6000
2x²-20x=6000
2x²-20x-6000=0
x²-10x-3000=0
We solve this quadratic equation:
x=[10⁺₋√(100-4*1*-3000)]/2=[10⁺₋√(100+12000)]/2=
=(10⁺₋110)/2
we have two solutions:
x₁=(10-110)/2=-50, invalid solution.
x₂=(10+110)/2=60
x=60
2x-20=2(60)-20=120-20=100
Solution: the length is 100 m, and the width is 60 m.
To check:
Area=100 m*60 m=6000 m²
The twice of width is =2(60 m)=120 m,
20 m less than twice its width is: 120 m-20 m=100 m=the length.
Answer:
answer D ( if i interpreted your question correctly )
Step-by-step explanation:
Sqrt (c^2) = √(c^2) = C
What is the order of √5 , -0.1, -5/3 , 0.7, √2 from least to greatest? A. √5, √2 , 0.7, -5/3 , –0.1 B. –0.1, 0.7, √2 , √5, -5/3
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-5/3, -0.1, 0.7, -/2, -/5 Which is C
Can you show the answer choices but I believe is 18
