Statistic bias given that the sample is not big enough
So that you have all requirement met
about 5-10
vocational school
<h3>Answer:</h3>
- A — 1
- B — ∑[k=0..2] 15Ck(.24^k)(.76^(15-k))
- D — 12 and 3.1
- A — 0.1091
- B — 0.83 ...
<h3>Explanation:</h3>
1. The probability is 0.52 that the officer will pull over a driver and then the expected number more. So, if x is the expected number of drivers pulled over until one is not texting, we have ...
... x = 0.52(1+x)
... 0.48x = 0.52
... x = 0.52/0.48 = 13/12 = 1 1/12 ≈ 1 . . . . matches selection A
(<em>Comment on this result</em>: I find it interesting that these are the odds in favor of finding a driver who texts. That is, if the probability of texting is 0.98, the odds are 49:1 that a driver will be texting, and the expected number of pull-overs is 49.)
2. The probability of at most 2 being cured is the probability of 0, 1, or 2 being cured. You need to add up those probabilities. The sum in answer selection B does that.
3. The mean of a binomial distribution is ...
... μx = np = 60·0.2 = 12
... σx = √(np(1-p)) = √(12·0.8) ≈ 3.0984
These match selection D.
4. 20C14(0.8^14)(0.2^6) = 38760·.043980·0.000064 ≈ 0.109100 . . . matches A
5. mean(x) = 0.94; mean(x^2) = 1.58, so ...
... σx = √(1.58 -0.94²) ≈ 0.83 . . . . matches selection B
Answer:
Carbon/Radiocarbon Dating
Explanation:
Carbon dating yields some of the most accurate results for aging samples around 50,000 years old, and can be as accurate as within a few decades of the exact year. Carbon dating uses the relative proportions of the carbon isotopes carbon-12 and carbon-14 that the fossil/sample contains to pinpoint an almost exact time.
The answer is currency. It refers to the <span>paper money and coins that are in circulation in a nation and that make up its money supply. The currency per nation may differ depending on the state of the economy. Equivalent rates regarding the currency between countries may also change depending on the economy's strength.</span>
