All categories

4 years ago

Evaluate log 8 12 a 0.84 b 0.67 c 1.50 d 1.19

Mathematics

1 answer:

adelina 88 [10]4 years ago

7 0

Answer:

Step-by-step explanation:

the answer's 1.19?........

You might be interested in

Helppppppppppppppppppppppppppppppppppppppppppp

Llana [10]

Answer:

612 Children's dresses

Step-by-step explanation:

837 + 958 = 1795

2407 - 1795 = 612

5 0

3 years ago

The degree measure of the vertex angle is x + 21 . The

zimovet [89]

The equation would be X +21+ 2X +17+ 2X +17 equals 180 when solved you get X equals 25

3 0

4 years ago

(−4)−(−2)–{(−5)–[(−7)+(−3)–(−8)]}

garik1379 [7]

Answer:

Step-by-step explanation:

(−4)−(−2)–{(−5)–[(−7)+(−3)–(−8)]}

-4 + 2 - {-5 - [-7 - 3 + 8]}

-2 - [-5 + 7 + 3 - 8]

-2 - (-3)

-2 + 3

7 0

3 years ago

Suppose a constellation of stars is plotted on a coordinate plane. The coordinates of one star are (0,-8). The

GarryVolchara [31]

Answer:

Step-by-step explanation:

4 0

3 years ago

Use Stokes' Theorem to calculate the circulation of the field F around the curve C in the indicated direction. F = 3yi + yj+zk

jok3333 [9.3K]

Answer:

$\int \int \bigtriangledown F\ X\ dS = \int F\cdot dr$ = 12π

Step-by-step explanation:

The field F is given by:

$F = 3y\hat{i} + y\hat{j}+z\hat{k}$ (1)

The curve C is the ellipse:

$\frac{x^2}{4}+\frac{y^2}{64}=1\\\\(\frac{x}{2})^2+(\frac{y}{8})^2=1$

In order to calculate the circulation of F around the curve C, you first find the parametric equation for the given ellipse.

The general form of an ellipse equation is:

$(\frac{x}{a})^2+(\frac{y}{b})^2=1$

The parametric equation is:

$r(t)=acost \hat{i} + bsint\hat{j}=2cost\hat{i}+8sint\hat{j}$ (2)

The Stokes's theorem is given by the following identity:

$\int \int \bigtriangledown F\ X\ dS = \int F\cdot dr$

The path integral is also:

$\int F\cdot dr=\int F(r(t))\cdot dr(t)$ (3)

For F(r(t)) and dr(t) you obtain:

$F(r(t))=3(8sint)\hat{j}+(8sint)\hat{j}+(z)\hat{k}\\\\dr(t)=(-2sint\hat{i}+8cost\hat{j}+0\hat{k})dt\\\\F(r(t))\cdot dr(t)=(-48sin^2t+64cos^2t)dt$

Next, in the equation (3) you obtain:

$\int_0^{2\pi} (-48sin^2t+64cos^2t)dt=\int_0^{2\pi}(-\frac{48}{2}(1-cos2t)+\frac{64}{2}(1+cos2t))dt\\\\=\int_0^{2\pi}(-24+24cos2t+32+32cos2t)dt\\\\=\int_0^{2\pi}(6+56cos2t)dt\\\\=[6t+56sin2t]_0^{2\pi}=[6(2\pi)-0]=12\pi$

The circulation of the field around C is 12π

5 0

3 years ago