Answer
1/2+2×(sqrt3)^2+x.(sqrt3/2)^2=8+1^2+1/2
1/2+2×3+x.3/4=8+1+1/2
1/2-1/2+6+x.3/4=9
x.3/4=9-6
x.3×4=3
x.3=3×4
x.3=12
x=12/3
x=4.
so, the value of x is 4.
hope it helps you.
The given equation is
where h is the height, in feet, of a ball and t is the time, in seconds.
<u>Part a: The height of the ball when t = 2 seconds:</u>
The height of the ball above the ground 2 seconds after it is released can be determined by substituting t= 2 in the equation
, we get;

Simplifying the terms, we get;


Thus, the height of the ball after 2 seconds is 100 feet.
<u>Part b: The height of the ball when t = 4 seconds:</u>
The height of the ball above the ground 4 seconds after it is released can be determined by substituting t = 4 in the equation
, we get;

Simplifying the terms, we get;


Thus, the height of the ball after 4 seconds is 68 feet.
In a plot of the probability of finding the electron in the hydrogen ground state versus the distance from the nucleus, the maximum occurs (A) at a0. the first Bohr radius.
<h3>
What is an electron?</h3>
- The electron is a subatomic particle with a negative one elementary charge electric charge.
- Electrons are the first generation of the lepton particle family and are widely regarded as elementary particles due to the lack of known components or substructure.
Electron in the hydrogen:
- Hydrogen has the simplest electron configuration to write because it just contains one electron.
- There is essentially only one electron surrounding the Hydrogen nucleus.
- Because hydrogen only has one electron, its configuration is 1s1.
- The maximum occurs at a0, the first Bohr radius, in a plot showing the chance of finding the electron in the hydrogen ground state vs the distance from the nucleus.
Therefore, in a plot of the probability of finding the electron in the hydrogen ground state versus the distance from the nucleus, the maximum occurs (A) at a0. the first Bohr radius.
Know more about electrons here:
brainly.com/question/860094
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The complete question is given below:
In a plot of the probability of finding the electron in the hydrogen ground state versus the distance from the nucleus, the maximum occurs:
A. at a0. the first Bohr radius
B. at slightly less than a0
C. at slightly more than a0
D. at 2 a0
E. at a0/2
Answer:
5
Step-by-step explanation:
25/5
=5✖️5=25
=5/1
Answer:
22(12) - 18
Step-by-step explanation: