Question

A stadium has 53,000. Seats sell for ​$ 42 in Section​ A, ​$ 36 in Section​ B, and ​$ 30 in Section C. The number of seats in Section A equals the total number of seats in Sections B and C. Suppose the stadium takes in ​$ 1,996,800 from each​ sold-out event. How many seats does each section​ hold

Answer 1

A =  B + C = 53,000 / 2 = 26,500

section A: 26,500 (seats) x 42 = $1,113,000
$1,996,800 - $1,113,000 = $883,800

So now 
B + C  = 26,500 so B = 26,500 - C
36B + 30C = $883,800

substitute B = 26,500 - C into 36B + 30C = $883,800

36B + 30C = $883,800
36(26,500 - C)  + 30C = $883,800
954,000 - 36C + 30C = $883,800
              -6C = -70,200
                 C =11,700

B = 26,500 - C
B = 26,500 - 11,700
B = 14,800

Answer
A: 26,500 seats
B: 14,800 seats
C: 11,700 seats