2a^2+4a+1 is equivalent to 4a+4/2a*a^2/a+1
Answer:
Step-by-step explanation:
The equation of a straight line can be represented in the slope-intercept form, y = mx + c
Where c = intercept
For two lines to be perpendicular, the slope of one line is the negative reciprocal of the other line. The equation of the given line is
y = 2x - 2
Comparing with the slope intercept form,
Slope, m = 2
This means that the slope of the line that is perpendicular to it is -1/2
The given points are (-3, 5)
To determine c,
We will substitute m = -1/2, y = 5 and x = - 3 into the equation, y = mx + c
It becomes
5 = -1/2 × - 3 + c
5 = - 3/2 + c
c = 5 + 3/2
c = 13/2
The equation becomes
y = -x/2 + 13/2
Answer:
Step-by-step explanation:
In order to find the value of ∠EFB here, we have to note our angle relationships.
We know that ∠CFE is already 90°. We also know that ∠CFA is 90°. Angle ∠AFB is inside ∠CFA. Since we know the measure of ∠AFB, we can find the measure of ∠BFC.
Now that we know ∠CFE and ∠BFC, which together make ∠BFE, we can add these angles up.
Hope this helped!
Answer:
Step-by-step explanation:
m<4= 109*
m<3= 71*
m<1= 71*
