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Alenkinab [10]
2 years ago
8

If the perimeter of a square is 18.48 cm, how long is one side of the square?

Mathematics
1 answer:
Andrew [12]2 years ago
6 0
One side is 4.62 cm long
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3/4 of a mile until he reaches the end of the path.

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Step-by-step explanation:

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This season, the probability that the Yankees will win a game is 0.5 and the probability that the Yankees will score 5 or more r
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2 years ago
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Solve for x.<br> 7(1x - 3) = 4(x + 5)
alexandr1967 [171]

Answer:

x = 41/3

General Formulas and Concepts:

<u>Pre-Algebra</u>

  • Order of Operations: BPEMDAS
  • Equality Properties

Step-by-step explanation:

<u>Step 1: Define equation</u>

7(1x - 3) = 4(x + 5)

<u>Step 2: Solve for </u><em><u>x</u></em>

  1. Simplify:                                        7(x - 3) = 4(x + 5)
  2. Distribute:                                     7x - 21 = 4x + 20
  3. Subtract 4x on both sides:          3x - 21 = 20
  4. Add 21 on both sides:                  3x = 41
  5. Divide 3 on both sides:                x = 41/3

<u>Step 3: Check</u>

<em>Plug in x to verify it's a solution.</em>

  1. Substitute:                    7(1(41/3) - 3) = 4(41/3 + 5)
  2. Multiply:                        7(41/3 - 3) = 4(41/3 + 5)
  3. Subtract/Add:               7(32/3) = 4(56/3)
  4. Multiply:                        224/3 = 224/3

Here, we see that 224/3 is indeed equivalent to 224/3. ∴ x = 41/3 is a solution to the equation.

And we have our final answer!

6 0
2 years ago
A survey of 85 families showed that 36 owned at least one DVD player. Find the 99% confidence interval estimate of the true prop
Katyanochek1 [597]

Answer:   (0.367,\ 0.473)

Step-by-step explanation:

The confidence interval for population mean is given by :-

\hat{p}\pm z_{\alpha/2}\sqrt{\dfrac{\hat{p}(1-\hat{p})}{n}}

, where \hat{p} is the sample proportion, n is the sample size , z_{\alpha/2} is the critical z-value.

Given : Significance level : \alpha:1-0.99=0.01

Sample size : n= 85

Critical value : z_{\alpha/2}=2.576

Sample proportion: \hat{p}=\dfrac{36}{85}\approx0.42

Now, the  99% confidence level will be :

\hat{p}\pmz_{\alpha/2}\sqrt{\dfrac{\hat{p}(1-\hat{p})}{n}}\\\\=0.42\pm(2.576)\sqrt{\dfrac{0.42(1-0.42)}{85}}\\\\\approx0.42\pm0.053\\\\=(0.42-0.053,\ 0.42+0.053)=(0.367,\ 0.473)

Hence, the  99% confidence interval estimate of the true proportion of families who own at least one DVD player is  (0.367,\ 0.473)

3 0
2 years ago
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