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Alenkinab [10]
3 years ago
8

If the perimeter of a square is 18.48 cm, how long is one side of the square?

Mathematics
1 answer:
Andrew [12]3 years ago
6 0
One side is 4.62 cm long
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How many solutions are there for the system x^2+4y^2=100 and 4y-x^2=-20
never [62]
There are 5 solutions for this system.

x^2 + 4y^2 = 100  ____1
4y - x^2 = -20  ____2
Add both 1 & 2 together. x^2 gets cancelled
4y^2 + 4y = 80   (send 80 to the other side and divide by 4)
Then equation the becomes : y^2 + y -20 =0
Now factorise the equation: (y+5) (y-4) = 0
Solve for y :  y = -5 and y = 4
Using the values of y to find the values of x. From equation 1:
x^2 = 100 - 4y^2    x = /100 - 4y^2  (/ means square root) Replace values of y
y = -5, x = /100 - 4(-5)^2 = /100 - 100 = 0
y = 4, x = /100 - 4(4)^2 = / 100 - 64 = /36 = -6 or 6
Thus we have 6 solutions y = -5, 4 and x = -6, 0, 6
6 0
3 years ago
What is num 2?? I need this done by tonight!
timama [110]
Maybe absolute value
3 0
3 years ago
Please Help Meeee! Its a multiple answers..​
Lelechka [254]

Answer:

B C E

Step-by-step explanation:

trust me... its too hard to explain

3 0
3 years ago
Assume that the probability that a baseball player will get a hit in any one at bat is 0.250. What is the probability that he wi
Yanka [14]

Answer: 0.0791

Step-by-step explanation:

Given : The probability that a baseball player will get a hit in any one at bat is 0.250.

Let x be the first hit.

According to the geometric probability , the probability that x (th) trial is the first success =P(X=x)=(1-p)^{x-1}p , where p is the probability of getting success in each trial.

As per given p= 0.250

Then, the probability that he will get his first hit on his 5th at bat will be :

P(X=x)=(1-0.25)^{5-1}(0.25)\\\\=(0.75)^4(0.25)\\\\=0.0791015625\approx0.0791

Hence, the probability that he will get his first hit on his 5th at bat is 0.0791 .

7 0
3 years ago
Plsssssssss help meeee
loris [4]

Answer:

1

Step-by-step explanation:

0

=

9

3

5 0
3 years ago
Read 2 more answers
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