odds against a randomly chosen household having a cat if the probability of the event that a randomly chosen household has a cat

Question

4 years ago

12

is .21

1 answer:

Snowcat [4.5K] · Answer 1 · 2022-01-13T15:48:43+03:00

8 0

Step-by-step explanation:

Odds against = failures / successes

Probability = successes / (successes + failures)

0.21 = cats / (cats + no cats)

1 / 0.21 = (cats + no cats) / cats

4.76 = 1 + (no cats / cats)

3.76 = no cats / cats

So the odds against are 3.76 to 1.