Question

I should be able to solve this but some reasons I just can't see the steps and the right answer.

Answer 1

$sin(20^o)= \frac{opposite}{hypotenuse} = \frac{19}{x} \ \ \ \to \\ \\ x = \frac{19}{sin(20^o)}= \frac{19}{0.342} \approx 55.6$