Answer: total distance - 135 = 50 (hours - 2.5)
Here we want to see which one of the given graphs is the one with the correct relationship between distance in centimeters and meters. We will see that the correct option is the first graph.
<h3>Working with changes of scale.</h3>
So we know that each centimeter on the map must represent 4 meters in reality, this is a change of scale, so the scale is:
1cm = 4m
First, this relation is linear (each centimeter will always be equal to 4 meters) so the two bottom options that are not linear can be discarded, so we only have the first and second graph.
If you read them, you can see that in the second one 1 meter is equivalent to something near 5 cm, so this is also incorrect.
The only graph that shows a correct scale is the first one, where for each increment of 1 unit on the horizontal axis (the one in centimeters) we have an increase of 4 m (estimated). This means that 1cm = 4m, as in our change of scale.
So the correct option is the first graph.
If you want to learn more about changes of scale, you can read:
brainly.com/question/9302261
Answer:
Both 10 and 2
Step-by-step explanation:
Hope this helpsss
Well, we could try adding up odd numbers, and look to see when we reach 400. But I'm hoping to find an easier way.
First of all ... I'm not sure this will help, but let's stop and notice it anyway ...
An odd number of odd numbers (like 1, 3, 5) add up to an odd number, but
an even number of odd numbers (like 1,3,5,7) add up to an even number.
So if the sum is going to be exactly 400, then there will have to be an even
number of items in the set.
Now, let's put down an even number of odd numbers to work with,and see
what we can notice about them:
1, 3, 5, 7, 9, 11, 13, 15 .
Number of items in the set . . . 8
Sum of all the items in the set . . . 64
Hmmm. That's interesting. 64 happens to be the square of 8 .
Do you think that might be all there is to it ?
Let's check it out:
Even-numbered lists of odd numbers:
1, 3 Items = 2, Sum = 4
1, 3, 5, 7 Items = 4, Sum = 16
1, 3, 5, 7, 9, 11 Items = 6, Sum = 36
1, 3, 5, 7, 9, 11, 13, 15 . . Items = 8, Sum = 64 .
Amazing ! The sum is always the square of the number of items in the set !
For a sum of 400 ... which just happens to be the square of 20,
we just need the <em><u>first 20 consecutive odd numbers</u></em>.
I slogged through it on my calculator, and it's true.
I never knew this before. It seems to be something valuable
to keep in my tool-box (and cherish always).
