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umka2103 [35]
3 years ago
10

The set of the consecutive odd numbers 1, 3, 5, 7, ... , N has a sum of 400. How many numbers are in the set?

Mathematics
1 answer:
Amanda [17]3 years ago
3 0

Well, we could try adding up odd numbers, and look to see when we reach 400. But I'm hoping to find an easier way.

First of all ... I'm not sure this will help, but let's stop and notice it anyway ...
An odd number of odd numbers (like 1, 3, 5) add up to an odd number, but
an even number of odd numbers (like 1,3,5,7) add up to an even number.
So if the sum is going to be exactly 400, then there will have to be an even
number of items in the set.

Now, let's put down an even number of odd numbers to work with,and see
what we can notice about them:

         1, 3, 5, 7, 9, 11, 13, 15 .

Number of items in the set . . . 8
Sum of all the items in the set . . . 64

Hmmm.  That's interesting.  64 happens to be the square of 8 . 
Do you think that might be all there is to it ?

Let's check it out:

Even-numbered lists of odd numbers:

1, 3                                   Items = 2, Sum = 4
1, 3, 5, 7                           Items = 4, Sum = 16
1, 3, 5, 7, 9, 11                 Items = 6, Sum = 36
1, 3, 5, 7, 9, 11, 13, 15 . . Items = 8, Sum = 64 .

Amazing !  The sum is always the square of the number of items in the set !

For a sum of 400 ... which just happens to be the square of 20,
we just need the <em><u>first 20 consecutive odd numbers</u></em>.

I slogged through it on my calculator, and it's true.

I never knew this before.  It seems to be something valuable
to keep in my tool-box (and cherish always).


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marishachu [46]

Answer:

a) 286

b) 1,037,836,800

c) 285

Step-by-step explanation:

a) Since order is not important, the total possible number of ways to choose 10 players out of 13 is the following combination:

C(13,10)=\frac{13!}{(13-10)!10! } \\C(13,10)=\frac{13*12*11*10!}{(3*2*1)10! }\\C(13,10) = 286

b) The total number of possibilities to assign positions by the selecting 10 players is the permutation of 13 players for 10 positions:

P(13,10) = \frac{13!}{(13-10)!}\\P(13,10) = 13*12*11*10*9*8*7*6*5*4\\P(13,10) =1,037,836,800

c) The number of ways to pick 10 players including at least one woman is equal to the total number of ways to pick 10 players (found in item a) minus the the number of ways to pick 10 players without picking a single woman.

Since there 10 male players for 10 positions, there is only one possible way to pick a team without women, therefore:

P=286-1 =285

6 0
3 years ago
Line a is parallel to line b, m 6=85 and m 3=2x. Find m 1.
FromTheMoon [43]
The sum of the angles <6 and <3 must be 180. Since <3 and <1 are opposed to the top, their measure are equal. We need then to calculate the measure of angle >3 = 180 - <6 = 180-85=95

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8 0
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F(x) = x5 + 5x4 - 5x3 - 25x2 + 4x + 20
Pie

Answer:

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Step-by-step explanation:

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Lana71 [14]

Answer:

x = 14.7

Step-by-step explanation:

Use Law of Sines.

7/sin20=x/sin46

cross multiply

7sin46=xsin20

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x = 7sin46/sin20

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3 0
3 years ago
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NikAS [45]
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Two other sides = 5, so 5+5=10
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If you would like any more assistance with this type of questions, let me know and I will be able to further assist you. Thank you!
6 0
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