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umka2103 [35]
3 years ago
10

The set of the consecutive odd numbers 1, 3, 5, 7, ... , N has a sum of 400. How many numbers are in the set?

Mathematics
1 answer:
Amanda [17]3 years ago
3 0

Well, we could try adding up odd numbers, and look to see when we reach 400. But I'm hoping to find an easier way.

First of all ... I'm not sure this will help, but let's stop and notice it anyway ...
An odd number of odd numbers (like 1, 3, 5) add up to an odd number, but
an even number of odd numbers (like 1,3,5,7) add up to an even number.
So if the sum is going to be exactly 400, then there will have to be an even
number of items in the set.

Now, let's put down an even number of odd numbers to work with,and see
what we can notice about them:

         1, 3, 5, 7, 9, 11, 13, 15 .

Number of items in the set . . . 8
Sum of all the items in the set . . . 64

Hmmm.  That's interesting.  64 happens to be the square of 8 . 
Do you think that might be all there is to it ?

Let's check it out:

Even-numbered lists of odd numbers:

1, 3                                   Items = 2, Sum = 4
1, 3, 5, 7                           Items = 4, Sum = 16
1, 3, 5, 7, 9, 11                 Items = 6, Sum = 36
1, 3, 5, 7, 9, 11, 13, 15 . . Items = 8, Sum = 64 .

Amazing !  The sum is always the square of the number of items in the set !

For a sum of 400 ... which just happens to be the square of 20,
we just need the <em><u>first 20 consecutive odd numbers</u></em>.

I slogged through it on my calculator, and it's true.

I never knew this before.  It seems to be something valuable
to keep in my tool-box (and cherish always).


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2.The number of tickets sold to a play for each showing is 78, 84, 87, 80, 91, 95, and 80.
Luden [163]

Answer:

Min =78

The maximum is :

Max = 95

Now we can calculate the median since the sample size os n =7 the median would be the middle value at the position 4 from the dataset ordered and we got:

Median =84

Now we can find the quartile 1 we analyze the first 4 values  78, 80,80, 84 and the first quartile would be:

Q_1= \frac{80+80}{2}= 80

Now we can find the quartile 3 we analyze the last 4 values  84,87, 91, 95 and the third quartile would be:

Q_3= \frac{87+91}{2}=89

And finally the 5 number summary would be:

Min = 78, Q_1 = 80, Median=84, Q_3 = 89, Max=96

Step-by-step explanation:

We have the following data given:

78, 84, 87, 80, 91, 95, and 80.

The first step is order the dataset on increasing way and we got:

78, 80,80, 84,87, 91, 95

We can begin finding the minimum value and for this case is:

Min =78

The maximum is :

Max = 95

Now we can calculate the median since the sample size os n =7 the median would be the middle value at the position 4 from the dataset ordered and we got:

Median =84

Now we can find the quartile 1 we analyze the first 4 values  78, 80,80, 84 and the first quartile would be:

Q_1= \frac{80+80}{2}= 80

Now we can find the quartile 3 we analyze the last 4 values  84,87, 91, 95 and the third quartile would be:

Q_3= \frac{87+91}{2}=89

And finally the 5 number summary would be:

Min = 78, Q_1 = 80, Median=84, Q_3 = 89, Max=96

5 0
3 years ago
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